Re (1+ iz)| = 3

Q: dr VIr - 1|

A:

Q: 1/3y-9=1/10y

A: Here given as 13y-9=110y Here y is not equal to 0 and 3.

Q: | 8 - 3s | = 9/2

A: To solve: |8-3s|=92 Solution: |8-3s|=92 On simplifying further we get: |8-3s|=92⇒8-3s=±92…

Q: 9 – 4x > –3

A: The given inequality is 9-4x>-3

Q: Evaluate 4x - 4 а. dx ex2-2x-9 b. S dx 5-4x

A:

Q: Evaluate S (2x+3) dx x² (x²+1)

A:

Q: (-x - 3) + (3x + 8)

A: Here we have to solve the given expression.

Q: 1=x2 what is x?

A: The root of negative value is imaginary

Q: 2x 入t]

A:

Q: 7 x2 dx + 4x + 20 13

A:

Q: オッlda+ [xe -0 tye Ifre-y

A:

Q: 1/3p + 7 = 25

A:

Q: L'im 2x - 3

A:

Q: find -1 2 5+1 s(5+1)²

A:

Q: -2/w-3/4=3w-7/3

A: Consider the given equation.

Q: ID 2 = {(Xy) 2x=7

A:

Q: 3/x-5 + 2/x+4 = 5/7

A: Given,          3x-5+2x+4=57

Q: 2 x -dx 6. Jo 1-x

A:

Q: %3D when

A:

Q: How to 3x-2 gel 8x +4

A:

Q: Simplify  1/y+5/1/y-9

A: Case (i)If the given expression is,

Q: I have to write 0 in the form of a/b

A: write 0 in the form of a/b

Q: + 3x' + 3x -2

A: We have to evaluate the following definite integral: ∫24-3+x-5x2+3x3+3x4x2+x-2dx

Equations and Inequations

Equations and inequalities describe the relationship between two mathematical expressions.

Linear Functions

A linear function can just be a constant, or it can be the constant multiplied with the variable like x or y. If the variables are of the form, x2, x1/2 or y2 it is not linear. The exponent over the variables should always be 1.