[RCOOH], M[R’OH], M[HA], MInitial Rate, M•min¨23.0.350.350.504.600.620.350.508.140.350.810.5010.60.350.500.759,84Rate = k[RCOOH][R'OH]%3DRate = k[RCOOH][R'OH][HA]Rate = k[RCOOR']/{[RCOOH][R'OH]}%3DRate = k[R'OH]Rate = k[RCOOH]%DIdentify the rate-determining step based on the rate law you foundin question 23.25.0–HkiR-С-0—Н+ HAR-¢+A-k20–HGroup 10–H0–Hk3R-C+A-R-0–HR—C—0—Нk4О—НR-ó+A-Group 2H0–HR—С—0—нk5R+C-0–R'+ H2O+ HAR-ó+A-Group 3H.Step 2 or Step 3Step 1 or Step 2Step 1 or Step 3Step 2Step 1O Oo O O

Here we have to apply the rate law Rate law=k[RCOOH]a[R'OH]b[HA]c

[RCOOH], M [R’OH], M (HA], M Initial Rate, M-min¨ 0.35 0.35 0.50 4.60 0.62 0.35 0.50 8.14 0.35 0.81 0.50 10.6 0.35 0.50 0.75 9.84 Rate = k[RCOOH][R'OH] Rate = k[RCOOH][R'OH][HA] %3D Rate = k[RCOOR']/{[RCOOH][R'OH]} Rate = k[R'OH] Rate = k[RCOOH] %3D

[RCOOH], M [R’OH], M (HA], M Initial Rate, M-min¨ 0.35 0.35 0.50 4.60 0.62 0.35 0.50 8.14 0.35 0.81 0.50 10.6 0.35 0.50 0.75 9.84 Rate = k[RCOOH][R'OH] Rate = k[RCOOH][R'OH][HA] %3D Rate = k[RCOOR']/{[RCOOH][R'OH]} Rate = k[R'OH] Rate = k[RCOOH] %3D

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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[RCOOH], M [R’OH], M [HA], M Initial Rate, M-min 23. 0.35 0.35 0.50 4.60 0.62 0.35 0.50 8.14 0.35 0.81 0.50 10.6 0.35 0.50 0.75 9.84 Rate = k[RCOOH][R'OH] Rate = k[RCOOH][R'OH][HA] Rate = k[RCOOR']/{[RCOOH][R'OH]} Rate = k[R'OH] Rate = k[RCOOH] 26. The initial reaction rate for the reaction in question 23 can be followed spectrophotometrically by quenching the reaction and determining the amount of R'OH left by its reaction with the dichromate ion, Cr20-2-. Write a balanced equation for the reaction of Cr20,2- with R'OH in acid solution. For simplicity, you may assume R' is an ethyl group (CH3CH2) and the products of the reaction are Cr3+ and CH3COOH. ЗСНЗСН20Н() + 2Cr2072-(аq) + 16H+{аq) + 3СНЗСООН() 4C13+(aq) + 3CH3COOCH3(I) + 14H2O(1) --> 3CH3CH2OH(I) + 2Cr2072-(aq) + 16H+(aq) ЗСНЗСООН() + 11Н20() 4Cr3+(aq)+ + --> --> 4CR3+(aq)++ 3CH3CH2OH(I) + 2Cr2072-(aq) + 5H2O(I) ЗСНЗСООН() + 160H-(аq) CH3CH2OH(I) + Cr2072-(aq) 2Cr3+(aq)+ + CH3COOH(I) --> СНЗCН2ОH() + Cr2072-(aq) Cr3+(aq)+ +…
please explain
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