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Rc Vcc RB UCE UBE Vin(t) VBB Figure 12.7 A simple common-emitter amplifier that can be analyzed by load-line techniques. ig (µA) 25 20 15 10 5 - U'BE (V) 1.0 0.2 0.4 0.6 0.8 (a) Input Figure P12.18 iç (mA) 12 i25 μΑ 10 20 μΑ 8. 15 μΑ 10 μΑ 5μΑ UCE (V) 20 12 16 (b) Output 6. 4. 2.

Rc Vcc RB UCE UBE Vin(t) VBB Figure 12.7 A simple common-emitter amplifier that can be analyzed by load-line techniques. ig (µA) 25 20 15 10 5 - U'BE (V) 1.0 0.2 0.4 0.6 0.8 (a) Input Figure P12.18 iç (mA) 12 i25 μΑ 10 20 μΑ 8. 15 μΑ 10 μΑ 5μΑ UCE (V) 20 12 16 (b) Output 6. 4. 2.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Consider the circuit of Figure 12.7 on page 605. Assume that VCC=20 V, VBB=0.3 V, RB=40 kΩ, and RC=2 kΩ. The input signal is a 0.2-V-peak 1-kHz sinusoid given by vin(t)=0.2 sin(2000πt). The common-emitter characteristics for the transistor are shown in Figure P12.18. Determine the maximum, minimum, and Q-point values for vCE. What is the approximate voltage gain for this circuit? Why is the gain so small in magnitude?

Rc Vcc RB UCE UBE Vin(t) VBB Figure 12.7 A simple common-emitter amplifier that can be analyzed by load-line techniques.
Transcribed Image Text:Rc Vcc RB UCE UBE Vin(t) VBB Figure 12.7 A simple common-emitter amplifier that can be analyzed by load-line techniques.
ig (µA) 25 20 15 10 5 - U'BE (V) 1.0 0.2 0.4 0.6 0.8 (a) Input Figure P12.18 iç (mA) 12 i25 μΑ 10 20 μΑ 8. 15 μΑ 10 μΑ 5μΑ UCE (V) 20 12 16 (b) Output 6. 4. 2.
Transcribed Image Text:ig (µA) 25 20 15 10 5 - U'BE (V) 1.0 0.2 0.4 0.6 0.8 (a) Input Figure P12.18 iç (mA) 12 i25 μΑ 10 20 μΑ 8. 15 μΑ 10 μΑ 5μΑ UCE (V) 20 12 16 (b) Output 6. 4. 2.
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