Raw Data: {3.5,2.7,1.6,2.9,1.7,5.3,7.5,8.2,4.6,1.3,4.7,9.4,7.6,3.9,3.2,8.1,4.9,5.7,2.6,3.2,6.5,4.8,3.5,4.8,9.2,4.9,1.1,2,6.4,7.1}{3.5,2.7,1.6,2.9,1.7,5.3,7.5,8.2,4.6,1.3,4.7,9.4,7.6,3.9,3.2,8.1,4.9,5.7,2.6,3.2,6.5,4.8,3.5,4.8,9.2,4.9,1.1,2,6.4,7.1} The gap between the first and second class is 0.1. What number should you subtract from each lower limit and add to each upper limit to find the class boundaries? 0.12=0.12=Answer Class Lower Class Boundary Upper Class Boundary 1.1−2.71.1−2.7 1.1−0.05=1.051.1−0.05=1.05 2.7+0.05=2.752.7+0.05=2.75 2.8−4.42.8−4.4 2.8−0.05=2.8−0.05= Answer 4.4+0.05=4.454.4+0.05=4.45 4.5−6.14.5−6.1 Answer −0.05=4.45−0.05=4.45 6.1+0.05=6.156.1+0.05=6.15 6.2−7.86.2−7.8 6.2−6.2− Answer =6.15=6.15 7.8+0.05=7.8+0.05= Answer 7.9−9.57.9−9.5 Answer Answer Answer =7.85=7.85 Answer +0.05=9.55+0.05=9.55

Raw Data: {3.5,2.7,1.6,2.9,1.7,5.3,7.5,8.2,4.6,1.3,4.7,9.4,7.6,3.9,3.2,8.1,4.9,5.7,2.6,3.2,6.5,4.8,3.5,4.8,9.2,4.9,1.1,2,6.4,7.1}{3.5,2.7,1.6,2.9,1.7,5.3,7.5,8.2,4.6,1.3,4.7,9.4,7.6,3.9,3.2,8.1,4.9,5.7,2.6,3.2,6.5,4.8,3.5,4.8,9.2,4.9,1.1,2,6.4,7.1} The gap between the first and second class is 0.1. What number should you subtract from each lower limit and add to each upper limit to find the class boundaries? 0.12=0.12=Answer Class Lower Class Boundary Upper Class Boundary 1.1−2.71.1−2.7 1.1−0.05=1.051.1−0.05=1.05 2.7+0.05=2.752.7+0.05=2.75 2.8−4.42.8−4.4 2.8−0.05=2.8−0.05= Answer 4.4+0.05=4.454.4+0.05=4.45 4.5−6.14.5−6.1 Answer −0.05=4.45−0.05=4.45 6.1+0.05=6.156.1+0.05=6.15 6.2−7.86.2−7.8 6.2−6.2− Answer =6.15=6.15 7.8+0.05=7.8+0.05= Answer 7.9−9.57.9−9.5 Answer Answer Answer =7.85=7.85 Answer +0.05=9.55+0.05=9.55

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Question

Raw Data:

{3.5,2.7,1.6,2.9,1.7,5.3,7.5,8.2,4.6,1.3,4.7,9.4,7.6,3.9,3.2,8.1,4.9,5.7,2.6,3.2,6.5,4.8,3.5,4.8,9.2,4.9,1.1,2,6.4,7.1}{3.5,2.7,1.6,2.9,1.7,5.3,7.5,8.2,4.6,1.3,4.7,9.4,7.6,3.9,3.2,8.1,4.9,5.7,2.6,3.2,6.5,4.8,3.5,4.8,9.2,4.9,1.1,2,6.4,7.1}

The gap between the first and second class is 0.1. What number should you subtract from each lower limit and add to each upper limit to find the class boundaries? 0.12=0.12=Answer

Class	Lower Class Boundary	Upper Class Boundary
1.1−2.71.1−2.7	1.1−0.05=1.051.1−0.05=1.05	2.7+0.05=2.752.7+0.05=2.75
2.8−4.42.8−4.4	2.8−0.05=2.8−0.05= Answer	4.4+0.05=4.454.4+0.05=4.45
4.5−6.14.5−6.1	Answer −0.05=4.45−0.05=4.45	6.1+0.05=6.156.1+0.05=6.15
6.2−7.86.2−7.8	6.2−6.2− Answer =6.15=6.15	7.8+0.05=7.8+0.05= Answer
7.9−9.57.9−9.5	Answer Answer Answer =7.85=7.85	Answer +0.05=9.55+0.05=9.55

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The information is as follows: Month, Cases of Lyme Disease, Drowning Deaths: Month: January, February, March, April, May, June, July, August, September, October, November, December Cases of Lyme Disease: 3, 2, 2, 4, 5, 12, 22, 13, 6, 5, 4, 1 Drowning Deaths: 0, 1, 2, 1, 2, 9, 15, 5, 6, 3, 3, 1, 0 a) Compute the correlation coefficient for the data. b) Is there a significant linear relationship? c) Do you believe an increase in Lyme disease causes an increase in the number of drownings? d) A “lurking variable” is a variable that influences both of the variables (cases of Lyme disease and number of drownings) in a linear correlation study that is unknown or not accounted for in the study. Name one possible lurking variable that might cause the number of Lyme disease cases and drownings to be correlated.