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Consider Use them k=9.00×10^9 N.m^2/C^2 ε0= 8.85×10^-12 C^2/N.m^2 µ0=4π×10^-7 T.m/A mp=1.67×10^-27 kg me=9.11×10^-31 kg e=1.6×10^-19 C g=10.0 m/s^2 Do not approximate at all ???

A spherical surface of radius R=6.0 cm penetrates an infinite charged sheet with uniform surface charge density o-2.25 nC/m². The sheet passes by the center of the
sphere. Find the net electric flux OE (in Nm-/C) through the spherical surface.

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What is the potential energy of an electron at the point P of the capacitor shown in the figure? (e = 1.6 x 10 19 C) %3D 300 V OV 5.0 mm 3D 3D 1 mm 1 mm 1 mm 1 mm 1 mm
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Constants and other possibly useful numbers = 9.8m/s G= 6.67 x 10-11 Nm2 kg c = 3 x 10 m/s = 9.1 x 10-31 kg e 1.6 x 10-19C h = h/(2m): = 1.05 x 10-34 Js NA 6.02 x 1023 /mol kB 1.38 × 10-23 J/K %3D R = KBNA 8.31 R OK = -273°C latm = 1.01 x 10 Pa leV = 1.6 x 10-19J mol K Specific Heat (c) J/(kg K) kcal/(kg°C) Aluminum 900 0.215 387 0.0924 Соpper Gold 129 0.0308 Iron, steel 452 0.108 Water 4186 1.000 1. Find the ratio of the new/old periods of a pendulum if the pendulum were transported from Earth to the Moon, where the acceleration due to gravity is 1.63m/s2.
P2 = 50 Pa U, = ??? P1 = 200 Pa Ah =10 m υ, 10 m/s
The planet Earth, Jupiter, the Moon, and the Sun have the following values: mJ = 1.90x1027kg , mE = 5.97x1024kg , mM = 7.35x1022 kg , mS = 1.99x1030kg RJ = 6.99x107 m , RE = 6.37x106 m, RM = 1.74x106 m , RS = 6.96x108 m dEarth to Moon = 3.60x105 km , dEarth to Jupiter = 588x106m , dEarth to Sun = 150x106 km (a) Find the magnitude of the force of gravity acting on the planet Earth due to the planet Jupiter. (b) Find the potential energy between the planet Earth and the planet Jupiter. (c) Find the acceleration of gravity on the planet Jupiter.
2 8 Perform the following calculations: (6.02 × 10²3) × (7.1 × 103) = 4.2742 ×1027 (8.46 × 10-4) × (2.23 x 103) = 1.88 65 8×100 3.6 × 107/2.2 × 104 = 1.63 x 10" 9 Perform the following conversions: 27.03 cm X 3.3 × 10⁰ g X 83 mph X 3.33 × 10-³ mL X 75 μm x 4°C X 12 miles x 2.9 g X 11.7 mg x 3.62 × 10-³ L X 36 gallons X 100 yards X 77°F X 15 nm X -16°C X 29 µg X 30 = = = || = || = || = = Exploring Biology in the Laboratory 04 6.4 × 106/4.2 × 10-³ = 1,52 7.2 × 108 + 3.3 × 107 = 7.53×108 9.4 × 106 - 4.6 × 10³ = 8.94×106 nm kg km/h gallons mm °F mm pounds kg mL Ligns 3 °C m °F ounces 29x119 1590 00000 on sii byg مواد ola 3 omen 3 bab 8 a obim A M
the average density of an atom is approximately 103 kg/m3. The nucleus of an atom has a radius about 10-5 times that of the entire atom, and contains nearly all the mass of the atom. What is the approximate density, in kilograms per cubic meter, of a nucleus?
The Statue of Liberty in New York City is approximately 305 ft305 ft tall. How many U.S. dimes would be in a stack of the same height? Each dime is 1.35 mm1.35 mm thick. number of dimes: Each dime has a mass of 2.268 g.2.268 g. How much would the stack of dimes from the previous question weigh? mass: g What is the value, in dollars, of the same stack of dimes? value: dollars The 2017 U.S. gross domestic product (GDP) was valued at 19,390,604,000 dollars.19,390,604,000 dollars. How many Statue of Liberty‑height stacks of dimes are needed to match the GDP in value? number of stacks:
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