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• rate = k(CH3 CooC,Hs][NAOH] O rate = k(CH; COOC;Hs]*[N2OH] Submit Previous Answers v Correct The reaction order exponents indicate how sensitive the rate is to ch zero, the rate in independent of the concentration of the reactant. Wheo in the concentrations of reactants. For simple reactions, the exponents are usually small positive integers. For more complex reaction, the exponents can be negative, zero, or even fractional. When the order is the order is negative, the rate decreases as the concentration increases. For this case, first order in CH3 COOC2H5 means that the reaction rate depends linearly on the concentration of CH3 COOC;Hs. For example, if (CH3COOC2H5] is doubled, the rate doubles (increases by a factor of 2). The same is true for NaOH. Part B The reaction of ethyl acetate with sodium hydroxide, CH3COOC,Hs (aq) + NaOH(aq) = CH3COONA(aq) + C2H5OH(aq) is first order in CH3COOC;Hs and first order in NAOH. If the concentration of CH3 COOC2H, was increased by half and the concentration of NaOH was increased by four, by what factor would the reaction rate increase? Express your answer numerically. > View Available Hint(s) Templates Symbols undo rego feset keyboard shortcuts Help

• rate = k(CH3 CooC,Hs][NAOH] O rate = k(CH; COOC;Hs]*[N2OH] Submit Previous Answers v Correct The reaction order exponents indicate how sensitive the rate is to ch zero, the rate in independent of the concentration of the reactant. Wheo in the concentrations of reactants. For simple reactions, the exponents are usually small positive integers. For more complex reaction, the exponents can be negative, zero, or even fractional. When the order is the order is negative, the rate decreases as the concentration increases. For this case, first order in CH3 COOC2H5 means that the reaction rate depends linearly on the concentration of CH3 COOC;Hs. For example, if (CH3COOC2H5] is doubled, the rate doubles (increases by a factor of 2). The same is true for NaOH. Part B The reaction of ethyl acetate with sodium hydroxide, CH3COOC,Hs (aq) + NaOH(aq) = CH3COONA(aq) + C2H5OH(aq) is first order in CH3COOC;Hs and first order in NAOH. If the concentration of CH3 COOC2H, was increased by half and the concentration of NaOH was increased by four, by what factor would the reaction rate increase? Express your answer numerically. > View Available Hint(s) Templates Symbols undo rego feset keyboard shortcuts Help

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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The rate of a chemical reaction depends on the concentrations of the reactants. Let's consider the general reaction between A and B: aA + 6B = cC + dD The dependence of the reaction rate on the concentration of each reactant is given by the equation called the rate law: rate = k[A]" [B]" where k is a proportionality constant called the rate constant. The exponent m determines the reaction order with respect to A, and n determines the reaction order with respect to B. The overall reaction order equals the sum of the exponents ( т+ n). For example, if m = 2 and n = 2 then rate = k[A]² [B]² and the overall reaction order is 2+2 = 4. The reaction orders are experimentally determined and usually not related to the reaction stoichiometric coefficients a and b.
Transcribed Image Text:The rate of a chemical reaction depends on the concentrations of the reactants. Let's consider the general reaction between A and B: aA + 6B = cC + dD The dependence of the reaction rate on the concentration of each reactant is given by the equation called the rate law: rate = k[A]" [B]" where k is a proportionality constant called the rate constant. The exponent m determines the reaction order with respect to A, and n determines the reaction order with respect to B. The overall reaction order equals the sum of the exponents ( т+ n). For example, if m = 2 and n = 2 then rate = k[A]² [B]² and the overall reaction order is 2+2 = 4. The reaction orders are experimentally determined and usually not related to the reaction stoichiometric coefficients a and b.
Consider the reaction of ethyl acetate with sodium hydroxide: CH;COOC,H; (aq) + NaOH(aq) = CH;COONA(aq) + C,H;OH(aq) The reaction is first order in NaOH and second order overall. What is the rate law? • View Available Hint(s) k[CH3 COOC2H5]* [NaOH]? rate = = k[CH3COOC2H5][NaOH]? = k[N2OH] rate = k[CH3COOC,H;] = k[CH3 COOC2H;][NaOH] = k[CH3COOC2H5]° [NaOH] Submit Previous Answers Correct The reaction order exponents indicate how sensitive the rate is to changes in the concentrations of reactants. For simple reactions, the exponents are usually small positive integers. For more complex reaction, the exponents can be negative, zero, or even fractional. When the order is zero, the rate in independent of the concentration of the reactant. When the order is negative, the rate decreases as the concentration increases. For this case, first order in CH3 COOC2H5 means that the reaction rate depends linearly on the concentration of CH3COOC2H5 . For example, if (CH3COOC2H5] is doubled, the rate doubles (increases by a factor of 2). The same is true for NaOH. Part B The reaction of ethyl acetate with sodium hydroxide, CHЗСOОС2Н5 (аq) + NaOH(aq) 3 CHзСОONa(aq) + CәHsОН(аq) is first order in CH3 COOC2H; and first order in NaOH. If the concentration of CH3 COOC2H; was increased by half and the concentration of NaOH was increased by four, by what factor would the reaction rate increase? Express your answer numerically. • View Available Hint(s) Templates Symbols undo regdo Teset keyboard shortcuts help Pesat
Transcribed Image Text:Consider the reaction of ethyl acetate with sodium hydroxide: CH;COOC,H; (aq) + NaOH(aq) = CH;COONA(aq) + C,H;OH(aq) The reaction is first order in NaOH and second order overall. What is the rate law? • View Available Hint(s) k[CH3 COOC2H5]* [NaOH]? rate = = k[CH3COOC2H5][NaOH]? = k[N2OH] rate = k[CH3COOC,H;] = k[CH3 COOC2H;][NaOH] = k[CH3COOC2H5]° [NaOH] Submit Previous Answers Correct The reaction order exponents indicate how sensitive the rate is to changes in the concentrations of reactants. For simple reactions, the exponents are usually small positive integers. For more complex reaction, the exponents can be negative, zero, or even fractional. When the order is zero, the rate in independent of the concentration of the reactant. When the order is negative, the rate decreases as the concentration increases. For this case, first order in CH3 COOC2H5 means that the reaction rate depends linearly on the concentration of CH3COOC2H5 . For example, if (CH3COOC2H5] is doubled, the rate doubles (increases by a factor of 2). The same is true for NaOH. Part B The reaction of ethyl acetate with sodium hydroxide, CHЗСOОС2Н5 (аq) + NaOH(aq) 3 CHзСОONa(aq) + CәHsОН(аq) is first order in CH3 COOC2H; and first order in NaOH. If the concentration of CH3 COOC2H; was increased by half and the concentration of NaOH was increased by four, by what factor would the reaction rate increase? Express your answer numerically. • View Available Hint(s) Templates Symbols undo regdo Teset keyboard shortcuts help Pesat
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