• Part BRank these automobiles based on the magnitude of the impulse needed to stop them, from largest to smallost.Rank from largest to smallest. To rank items as equivalent, overlap them. If the ranking cannot be determined, check the box below.> View Available Hint(s)Reset Help4000 kg500 kg1000 kg500 kg1000 kg2000 kg5 m/s10 m/s20 m/s10 m/s20 m/s5 m/slargestsmallestO The corrent ranking cannot he daterminertSubmit* PreviousMacBook ProSearch or Vp u RL Six automobiles are initially traveling at the indicated velocities. The automobiles have different masses and velocities. The drivers step on the brakes and all automobiles are brought to rest.Part ARank these automobiles based on the magnitude of their momentum before the brakes are applied, from largest to smallest.Rank from largest to smallest. To rank items as equivalent, overlap them. If the ranking cannot be determined, check the box below.Reset Help500 kg1000 kg500 kg2000 kg4000 kg1000 kg20 m/s10 m/s10 m/s5 m/s5 m/s20 m/slargestsmallestO The correct ranking cannot be determined.SubmitRequest AnswerPart B* PreviousMacBook ProG Search or type URL&346フ8ERYUDFGCB>

The largest impulse require For that car which has largest momentum. momentum P = mv. m= mass, v =…

Rank these automobiles based on the magnitude of the impulse needed to stop them, from largest to smallest. Rank from largest to smallest. To rank items as equivalent, overlap them. If the ranking cannot be determined, check the box below. > View Available Hint(s) Reset Help 500 kg 500 kg 1000 kg 2000 kg 4000 kg 1000 kg 20 m/s 5 m/s 20 m/s 10 m/s 5 m/s 10 m/s smallest largest O The correct rankinn cannot he daterminert Submit Previous MacBook Pro S0Dr ch o r tve O URL

Rank these automobiles based on the magnitude of the impulse needed to stop them, from largest to smallest. Rank from largest to smallest. To rank items as equivalent, overlap them. If the ranking cannot be determined, check the box below. > View Available Hint(s) Reset Help 500 kg 500 kg 1000 kg 2000 kg 4000 kg 1000 kg 20 m/s 5 m/s 20 m/s 10 m/s 5 m/s 10 m/s smallest largest O The correct rankinn cannot he daterminert Submit Previous MacBook Pro S0Dr ch o r tve O URL

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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A 1,400 kg car traveling at 31 m/s has a head-on collision with a 55,000 kg tank traveling at 5.0 m/s. What is the magnitude of the final velocity of the two vehicles if they stick together? Your answer: 4.1 m/s 5.6 m/s 18 m/s none of these (the answer is not close to any of these)
You drop a 15-g ball from a height of 1.5 m and it only bounces back to a height of 0.85 m. What was the total impulse on the ball when it hit the floor? (Ignore air resistance.) Express your answer to two significant figures and include the appropriate units. Enter positive value if the impulse is upward and negative value if the impulse is downward. F-Δt=__________
When there is motion is both directions, state which direction is positive at the START of the problem. For the impulse-momentum and the conservation of momentum problems: Plug your GIVEN VALUES into the equation FIRST then do the algebra. Use the following equations: F t = m vf -m vi m1 vi1 + m2 vi2 = m1 vf1 + m2 vf2 m1 vi1 + m2 vi2 = (m1 + m2) vf (m1 + m2) Vi = m1 vf1 + m2 vf2 3.) A 0.196 N bullet strikes a 10.00 kg block of wood, which is initally at rest. The bullet becomes lodged in the block of wood and afterwards both are traveling at 1.25 m/s. a. ) what was the velocity of the bullet before striking the block of wood?
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A bullet is traveling at 500m/s and is brought to rest by an impulse of 50NS. What is the mass of the bullet? GU SS + 2 | 2 | Page
When there is motion is both directions, state which direction is positive at the START of the problem. For the impulse-momentum and the conservation of momentum problems: Plug your GIVEN VALUES into the equation FIRST then do the algebra. Use the following equations: F t = m vf -m vi m1 vi1 + m2 vi2 = m1 vf1 + m2 vf2 m1 vi1 + m2 vi2 = (m1 + m2) vf (m1 + m2) Vi = m1 vf1 + m2 vf2 6.) Ball 1 : m1 = 8 slugs and vi1 = 3 ft/s to the RIGHT Ball 2: m2 = 4 slugs and vi2 = 0 Ball 3: m3 = 6 slugs and vi3 = 0 picture the three balls all siting on a flat surface with some space between them. AFTER ball 1 strikes ball 2, ball 1 is traveling at 1.5 ft/s to the LEFT AFTER ball 2 strikes ball 3, ball 2 is traveling at 3 ft/s to the LEFT a,) What is the direction (left or right) and final velocity of ball 3? Vf3 =? Show all unit conversions step by step, if any.
An oatmeal cookie is dropped on the floor. Is this an inelastic collision? Why or why not? It is because the cookie and floor can be considered one object. It is because the cookie and floor are stuck together. It is not because there is not momentum involved. It is not because the cookie and floor do not move away together as a unit.
When there is motion is both directions, state which direction is positive at the START of the problem. For the impulse-momentum and the conservation of momentum problems: Plug your GIVEN VALUES into the equation FIRST then do the algebra. Use the following equations: F t = m vf -m vi m1 vi1 + m2 vi2 = m1 vf1 + m2 vf2 m1 vi1 + m2 vi2 = (m1 + m2) vf (m1 + m2) Vi = m1 vf1 + m2 vf2 2. ) The baseball is traveling at 90 mph to the left towards the batter. The batter strikes the 0.05 slug baseball with a force of 50.00 lbs. The bat is in contact with the softball for 0.25 seconds. Assume that the baseball is traveling directly in the opposite direction after being hit with the bat. a. what is the velocity of the baseball after being hit by the batter? show all unit conversions-if any, step by step.
A 100-kg particle moves with an initial velocity of (4.0i, - 6.0j) m/s. If its velocity changes to v = (3.0i – 8.0j) m/s by the action of a force, determine The net work done on the particle. What principle would you use to solve this problem? The impulse on the particle. True or False: Impulse is equal to the rate of change of momentum.
Suppose F₁ = 2000 N. (Figure 1) You may want to review (Pages 262-266). Figure F, (N) F 0- 0 N. 2 4 6 1 of 1 -t (ms) Part A What impulse does the force shown in the figure exert on a 250 g particle? Express your answer in newton-seconds to two significant figures. WD ΑΣΦ J = Submit Previous Answers Request Answer X Incorrect; Try Again Provide Feedback ? N.S
A 1500 kg car traveling to the north is slowed down uniformly from initial velocity of 20 m/s by a 6000 N braking force acting opposite the car’s motion. Use the impulse-momentum theorem to answer the following questions What is the car’s velocity after 2.00 s? How far does the car move during 2.00 s? How long does it take the car to come to a complete stop?
"A 1-kg car travelling at 30 m/s decelerates coming to stop in 5 seconds, as a result of applying the break. What is the impulse experienced by the car?" 6000 Ns 18000 NS 12000 Ns 24000 Ns None of these