Rank the following compounds in order of increasing strength of their intermolecular forces, given the ΔH°vap listed for each. Place the compound with the strongest intermolecular forces (IMFs) at the top of the list. (Strongest to weaknest). Why is ΔHºvap for CH3SCH3 greater than ΔHºvap for CH3OCH3? A. CH3OCH3 is more polar. B. CH3SCH3 has stronger dipole–dipole attractions. C. CH3OCH3 can form hydrogen bonds. D. CH3SCH3 has stronger dispersion forces
Introduction to Organic Chemistry
The field of chemistry which deals with the studies of reactions, structures, and properties of organic compounds that comprise carbon bonded through covalent bonding is organic chemistry. The studies regarding the structure of organic compounds could be determined with the help of structural formulas. In order to know about the behavior of organic compounds, a study on the properties has to be done. Both physical properties and chemical properties, the origin of chemical reactivity come under the study regarding the properties of organic compounds. The chemical preparation of polymers, drugs, natural products, and the study of separate organic molecules in the lab come under the study of organic reactions.
Vinyl Group
Vinyl group is the name given to the functional group of -CH=CH2. It can be seen as an ethene molecule with one less hydrogen in number. Hence it is also called as ethenyl group at times.
Straight Chain Hydrocarbons
The requirement to identify each compound needs a richer number of words than informative prefixes like n and iso. The identification of organic molecules is made easier by the use of systematic nomenclature schemes. The organic chemistry nomenclature has two types: traditional and systematic. Common names arise in many forms, but share the characteristic that a link through name and form is unnecessary. The name that matches a certain structure clearly must be remembered as knowing a person's name. In contrast, systemic names, including an overall common set of laws, are locked specifically to the chemical structure.
Unsaturated Hydrocarbon
Following are few examples of alkenes with their general molecular as well as their structural formulas:
Conjugated Compounds in Organic Chemistry
The delocalization of electrons in a molecule is called conjugation in organic chemistry. This delocalisation process of electrons leads to the shortenings or elongations of chemical bonds, but at the same time it causes changes in the chemical properties in conjugated molecules as compared to the non-conjugated ones. For example, conjugated molecules absorb light at longer wavelengths.
Alpha Carbon And Alpha Protons
The carbon directly attached to the functional group in an organic molecule is referred to as the alpha carbon and the hydrogen attached to an alpha carbon are termed as the alpha hydrogens or alpha protons. These alpha carbon atoms and alpha hydrogen atoms are of importance because they undergo certain characteristic reactions in organic chemistry.
Organic compounds may have characteristic odors as well as other characteristic physical properties. For example, the distinct odor of the seashore at low tide results in part from the presence of dimethyl sulfide (CH3SCH3), a molecule with a similar structure to dimethyl ether (CH3OCH3). Ethanethiol (CH3CH2SH), also called mercaptan, is an isomer of dimethyl sulfide with a much less pleasant odor.
The table lists four related compounds and their enthalpies of vaporization (ΔH°vap) in kJ/mol.
| Compound | ΔH°vap (kJ/mol) |
|---|---|
| CH3OCH3 | 23 |
| CH3SCH3 | 28 |
| CH3CH2SH | 27.5 |
| CH3CH2OH | 42 |
Rank the following compounds in order of increasing strength of their intermolecular forces, given the ΔH°vap listed for each. Place the compound with the strongest intermolecular forces (IMFs) at the top of the list. (Strongest to weaknest).
Why is ΔHºvap for CH3SCH3 greater than ΔHºvap for CH3OCH3?
A. CH3OCH3 is more polar.
B. CH3SCH3 has stronger dipole–dipole attractions.
C. CH3OCH3 can form hydrogen bonds.
D. CH3SCH3 has stronger dispersion forces.
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 2 images
