Rank each of the following compounds in decreasing order of reactivity towards Friedel-Crafts alkylation. Most reactive = 1; if a compound will not react, rank it as "non" rather than assigning a numerical value. Compound A: fluorobenzene Compound B: anisole Compound C: iodobenzene Compound D: bromobenzene
Rank each of the following compounds in decreasing order of reactivity towards Friedel-Crafts alkylation. Most reactive = 1; if a compound will not react, rank it as "non" rather than assigning a numerical value. Compound A: fluorobenzene Compound B: anisole Compound C: iodobenzene Compound D: bromobenzene
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:Rank each of the following compounds in decreasing order of reactivity towards Friedel-Crafts alkylation.
Most reactive
1; if a compound will not react, rank it as "non" rather than assigning a numerical value.
Compound A: fluorobenzene
Compound B: anisole
Compound C: iodobenzene
Compound D: bromobenzene
Expert Solution

Step 1
Friedel Crafts alkylation is the replacement of an aromatic proton with an alkyl group. This happens through electrophilic attack on the aromatic ring with the help of a carbocation. The aromatic ring must be highly nucleophilic i.e. having high electron density to attack the electrophile.
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