This is a practice exam. I would like to know how to solve using excel or megastatRandom sampling from four normally distributed populations produced the following data: (You may find it useful to reference the F table.) TreatmentsA B C D −17 −20 −7 −15 −7 −18 −19 −13 −13 −12 −18 −19 −19 −8 −4 Click here for the Excel Data File a. Calculate the grand mean. (Negative value should be indicated by a minus sign. Round your answer to 2 decimal places.) b. Calculate SSTR and MSTR. (Round intermediate calculations to at least 4 decimal places and final answers to 4 decimal places.) c. Calculate SSE and MSE. (Round intermediate calculations to at least 4 decimal places and final answers to 4 decimal places.) d. Specify the competing hypotheses in order to determine whether some differences exist between the population means. multiple choice 1H0: μA ≤ μB ≤ μC; HA: Not all population means are equal.H0: μA = μB = μC; HA: Not all population means are equal.H0: μA ≥ μB ≥ μC; HA: Not all population means are equal. e-1. Calculate the value of the F(df1, df2) test statistic. (Round intermediate calculations to at least 4 decimal places and final answer to 3 decimal places.) e-2. Find the p-value. multiple choice 2p-value < 0.010.01 p-value < 0.0250.05 p-value < 0.100.025 p-value < 0.05p-value 0.10 f. At the 10% significance level, what is the conclusion to the test? multiple choice 3Do not reject H0 since the p-value is not less than significance levelReject H0 since the p-value is less than significance levelReject H0 since the p-value is not less than significance levelDo not reject H0 since the p-value is less than significance levelg. Interpret the results at α = 0.10.multiple choice 4We conclude that some means differ.We cannot conclude that some means differ.We cannot conclude that all means differ.We cannot conclude that population mean C is greater than population mean A.

GOTO EXCELDATA---->DATA ANALYSISDATA ANALYSIS---- > oNE WAY AnovaGive the four treatment…

Answered: Random sampling from four normally…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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This is a practice exam. I would like to know how to solve using excel or megastat

Random sampling from four normally distributed populations produced the following data: (You may find it useful to reference the F table.)

Treatments

−17

−20

−7

−15

−7

−18

−19

−13

−12

−18

−19

−8

−4

Click here for the Excel Data File

a. Calculate the grand mean. (Negative value should be indicated by a minus sign. Round your answer to 2 decimal places.)

b. Calculate SSTR and MSTR. (Round intermediate calculations to at least 4 decimal places and final answers to 4 decimal places.)

c. Calculate SSE and MSE. (Round intermediate calculations to at least 4 decimal places and final answers to 4 decimal places.)

d. Specify the competing hypotheses in order to determine whether some differences exist between the population means.

multiple choice 1

H₀: μ_A ≤ μ_B ≤ μ_C; H_A: Not all population means are equal.
H₀: μ_A = μ_B = μ_C; H_A: Not all population means are equal.
H₀: μ_A ≥ μ_B ≥ μ_C; H_A: Not all population means are equal.

e-1. Calculate the value of the F_{(df1, df2)} test statistic. (Round intermediate calculations to at least 4 decimal places and final answer to 3 decimal places.)

e-2. Find the p-value.

multiple choice 2

p-value < 0.01
0.01 p-value < 0.025
0.05 p-value < 0.10
0.025 p-value < 0.05
p-value 0.10

f. At the 10% significance level, what is the conclusion to the test?

multiple choice 3

Do not reject H₀ since the p-value is not less than significance level
Reject H₀ since the p-value is less than significance level
Reject H₀ since the p-value is not less than significance level
Do not reject H₀ since the p-value is less than significance level

g. Interpret the results at α = 0.10.

multiple choice 4

We conclude that some means differ.
We cannot conclude that some means differ.
We cannot conclude that all means differ.
We cannot conclude that population mean C is greater than population mean A.

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

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