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rample 6.16 EXAMPLE 6.16 1.94 slugs/ft' and v = Water, p= through 400 ft of 2-in-diameter pipe and several minor losses, as shown in Fig. E6.16. The rough- ness ratio is eld = 0.001. Compute the pump horsepower required. 0.000011 ft/s, is pumped betwecen two reservoirs at 0.2 ft/s. Screwed = 120ft regular 90° elbow Sharp exit = 20 fi Sharp entrance Half-open gate valve 12-in bend radius Pump Open globe valve E6.16 400 ft of pipe, d=

rample 6.16 EXAMPLE 6.16 1.94 slugs/ft' and v = Water, p= through 400 ft of 2-in-diameter pipe and several minor losses, as shown in Fig. E6.16. The rough- ness ratio is eld = 0.001. Compute the pump horsepower required. 0.000011 ft/s, is pumped betwecen two reservoirs at 0.2 ft/s. Screwed = 120ft regular 90° elbow Sharp exit = 20 fi Sharp entrance Half-open gate valve 12-in bend radius Pump Open globe valve E6.16 400 ft of pipe, d=

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Example 6.16 EXAMPLE 6.16 Water, p= 1.94 slugs/ft' and v = 0.000011 ft/s, is pumped between two reservoirs at 0.2 ft'/s through 400 ft of 2-in-diameter pipe and several minor losses, as shown in Fig. E6. 16. The rough- ness ratio is eld = 0.001. Compute the pump horsepower required. Screwed =120 ft regular 90° elbow Sharp exit = 20 f Sharp Half-open entrance gate valve 区 12-in bend radius Pump Open globe valve E6.16 400 ft of pipe, d = Solution
Transcribed Image Text:Example 6.16 EXAMPLE 6.16 Water, p= 1.94 slugs/ft' and v = 0.000011 ft/s, is pumped between two reservoirs at 0.2 ft'/s through 400 ft of 2-in-diameter pipe and several minor losses, as shown in Fig. E6. 16. The rough- ness ratio is eld = 0.001. Compute the pump horsepower required. Screwed =120 ft regular 90° elbow Sharp exit = 20 f Sharp Half-open entrance gate valve 区 12-in bend radius Pump Open globe valve E6.16 400 ft of pipe, d = Solution
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