Radiation from a distant neutron star is found by a satellite far from Earth to have wavelength λ = 3 nm. a) What is the ratio δλ/λ, where δλ is the difference with respect to the measurement by a detector on the surface of the Earth? The Schwarzschild radius of the Earth is 8.7 mm, while its actual radius is 6.4 × 106 m. b) What is the ratio δ′ λ/λ, where δ′ λ is the difference with respect to the wavelength of the same radiation at the time of emission from the neutron star’s surface? Assume that the neutron star’s actual radius is three times its (typically 4 km) Schwarzschild radius.
Radiation from a distant neutron star is found by a satellite far from Earth to have wavelength λ = 3 nm. a) What is the ratio δλ/λ, where δλ is the difference with respect to the measurement by a detector on the surface of the Earth? The Schwarzschild radius of the Earth is 8.7 mm, while its actual radius is 6.4 × 106 m. b) What is the ratio δ′ λ/λ, where δ′ λ is the difference with respect to the wavelength of the same radiation at the time of emission from the neutron star’s surface? Assume that the neutron star’s actual radius is three times its (typically 4 km) Schwarzschild radius.
Related questions
Question
Radiation from a distant neutron star is found by a satellite far from Earth to have wavelength λ = 3 nm.
a) What is the ratio δλ/λ, where δλ is the difference with respect to the measurement by a detector on the surface of the Earth? The Schwarzschild radius of the Earth is 8.7 mm, while its actual radius is 6.4 × 106 m.
b) What is the ratio δ′ λ/λ, where δ′ λ is the difference with respect to the wavelength of the same radiation at the time of emission from the neutron star’s surface? Assume that the neutron star’s actual radius is three times its (typically 4 km) Schwarzschild radius.
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 5 steps with 3 images