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R2 R1 t = 0 S For the circuit shown in the figure, the switch S is closed at t = 0. If R, = 4R/3 and R2 = 4R/3, find the current in the battery as a function of time. 28 a) I = 4e-2t/RC + R 38 38 b) I : e-3t/2RC + 2R 2R 38 e-3t/4RC 4R 38 c) I 4R d) I = e-4t/3RC 3R 3R 28 e) I = 2 e-2t/3RC + 3R 3R + +

R2 R1 t = 0 S For the circuit shown in the figure, the switch S is closed at t = 0. If R, = 4R/3 and R2 = 4R/3, find the current in the battery as a function of time. 28 a) I = 4e-2t/RC + R 38 38 b) I : e-3t/2RC + 2R 2R 38 e-3t/4RC 4R 38 c) I 4R d) I = e-4t/3RC 3R 3R 28 e) I = 2 e-2t/3RC + 3R 3R + +

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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+ R2 R1 t = 0 S For the circuit shown in the figure, the switch S is closed at t = 0. If R, = 4R/3 and R, = 4R/3, find the current in the battery as a function of time. a) I =e 28 o-2t/RC 28 + R R 38 b) I e-3t /2RC 38 + 2R 2R 38 38 c) I e-3t/4RC + 4R 4R d) I = 3R e-4t/3RC + 3R e) = 3R 2E e-2t/3RC + 28 3R
Transcribed Image Text:+ R2 R1 t = 0 S For the circuit shown in the figure, the switch S is closed at t = 0. If R, = 4R/3 and R, = 4R/3, find the current in the battery as a function of time. a) I =e 28 o-2t/RC 28 + R R 38 b) I e-3t /2RC 38 + 2R 2R 38 38 c) I e-3t/4RC + 4R 4R d) I = 3R e-4t/3RC + 3R e) = 3R 2E e-2t/3RC + 28 3R
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