ELTE 108 Homework 6Circuit Four:R2 = 236 QR3 = 244 QE2 =Ez =12 =I3 =R = 30 QE, =I =R = 160 2E =ET = 240 VR7 =IT =0610 assign ELTE108 Homework 06_2011-11-04ACC.docxCircuits: ver 2011-11-04 mjfPage 5 of 6

In the circuit shown in question, the resistor R2 is in series with resistor R3 and series…

Answered: R2 = 236 Q R3 = 244 Q Ez = E, = 3 = R =…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Question

ELTE 108 Homework 6
Circuit Four:
R2 = 236 Q
R3 = 244 Q
E2 =
Ez =
12 =
I3 =
R = 30 Q
E, =
I =
R = 160 2
E =
ET = 240 V
R7 =
IT =
0610 assign ELTE108 Homework 06_2011-11-04ACC.docx
Circuits: ver 2011-11-04 mjf
Page 5 of 6

Expert Solution

Step 1

In the circuit shown in question, the resistor R₂ is in series with resistor R₃ and series combination is in parallel with resistor R₄. The resistor R₁ is in series with the complete parallel combination. Thus, the total resistance seen by the voltage source is given by:

The total current supplied by the voltage source is the ratio of the voltage of the voltage source and the resistance across the voltage source terminal:

The current flowing in resistor R₁ is equal to the current supplied by the voltage source which is 0.16 A because the resistor is in series with the voltage source. To calculate the voltage across the resistor R₁, apply Ohm’s Law across resistor:

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