R120 General Chemistry F2020 Name: Titration of an Unknown Acid: V, = 25.00 mL Initial Volume Concentration of Final Volume Volume of NaOH (V.) (mL) (V.) (mL) used (mL) V Unknown Acid (M) Flask 1 0.28 25.05 24.77 Flask 2 0.00 25.15 25.15 Flask 3 0.10 25.25 25.15 M Average Acid Concentration: % error: Note: Unknown acid is HCI, so 1 mol HCI gives 1 eq H* for an acid/base titration Given Value: 0.1985 M HCI Calculations: Na. OH caq) + HA caa) → NacI caq) t HzO (e) Average NaOH molayrky: .1410M Conclusion: 1. Where do you think errors could come from in the experiment? 2. How would you modify the experiment to improve % error?
R120 General Chemistry F2020 Name: Titration of an Unknown Acid: V, = 25.00 mL Initial Volume Concentration of Final Volume Volume of NaOH (V.) (mL) (V.) (mL) used (mL) V Unknown Acid (M) Flask 1 0.28 25.05 24.77 Flask 2 0.00 25.15 25.15 Flask 3 0.10 25.25 25.15 M Average Acid Concentration: % error: Note: Unknown acid is HCI, so 1 mol HCI gives 1 eq H* for an acid/base titration Given Value: 0.1985 M HCI Calculations: Na. OH caq) + HA caa) → NacI caq) t HzO (e) Average NaOH molayrky: .1410M Conclusion: 1. Where do you think errors could come from in the experiment? 2. How would you modify the experiment to improve % error?
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:R120 General Chemistry
Name:
F2020
Titration of an Unknown Acid: Va = 25.00 mL
Concentration of
Unknown Acid (M)
Initial Volume
Final Volume
Volume of NaOH
(V.) (mL)
(V:) (mL)
used (mL) Vb
Flask 1
0.28
25.05
24.17
Flask 2
0.00
25.15
25.15
Flask 3
D.10
25.25
25.15
M
Average Acid Concentration:
% error:
Note: Unknown acid is HCl, so 1 mol HCl gives 1 eg H* for an acid/base titration
Given Value: 0.1985 M HCI
Calculations: Na OH (aq)
+ HA caa) → Nacl cag) t H20 (@)
Avernge NnOH molarty= .7410M
Conclusion:
1. Where do you think errors could come from in the experiment?
2. How would you modify the experiment to improve % error?
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