R1=2.6, R2=3.4, R3=4.8 Compose a junction rule equation for C and loop rule equations for abcfa and edcfe What is the current through each resistor? What is the power delivered to R3?
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- Figure shows a circuit with two batteries and three resistors.a. How much current flows through the 2.00-Ω resistor?b. What is the potential difference between points a and b in the circuit?Each of the five resistors has resistance R, and each of the five capacitors has capacitance C. The internal resistance of the battery is negligible. What is the time constant of the circuit shown in figure? R R R TC A. 5 RC B. RC C. 10 RC D. 25 RCThree resistors with values of 2 ?, 9 ?, and 11 ? respectively are connected in series to a 12 V power source. What is the equivalent resistance of the three resistors? What is the current in the 9 ? resistor? What is the potential difference across the 2 ? resistor?
- Kirchhoff Loop Problem Below is a circuit with 3 batteries and 2 resistors. Depending on the voltages of the batteries and the values of the resistors, either 1 or 2 of the batteries may be getting charged by the circuit. At least 1 battery has to be providing power to the circuit. But without solving Kirchhoff's Junction Rule and Kirchhoff's Loop Rule you don't know which is which. To determine which category the batteries fall into, you need to determine the magnitude and direction of the current in each leg of the circuit. The image below has the guessed direction of current, which is not necessarily correct. But you can use this to start your problem solving. The values for the resistances and batteries are below. R1 i3 + E1 E2 E3 A F R1 = 139.0 Ohms R2 = 164.0 Ohms E 1 = 4.20 V E 2 = 10.70 V € 3 = 14.11 V Find current i, in this circuit. Indicate direction by putting a - sign in front of the number if the actual current is traveling the opposite direction of the diagram. If the…R1 R, V %3D The circuit shown above has a 10 V battery connected to two resistors in series with R = 80 Q and R2 = 20Q. Select the correct current through resistor 1, I, and" resistor 2, 12. h=0.125 Amps 2=0.5 Amps h= 0.05 Amps, 12= 0.05 Amps O1=0.125 Amps, l2=0.05 Amps O4= 0.1 Amps, l2= 0.1 Amps 3D0.3125 Amps, 2=0.3125 AmpsIn the picture below there are 2 electromotive force with a large voltage of 12.5 V and an internal resistance of 0.75 Ohm arranged in series. Furthermore, the circuit with a series of resistance as shown in the picture. EJ & R₁=852 B R=1602 ·m R$40 R₂=1602 mmm. R₁=802 Calculate : a. The total resistance of the circuit. b. Strong current generated www.