R1 ww E1 R2 R3 E2 E D

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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3:33 D
ONIal al 53%
GenPhy2 Fourth Quarter Exam Part 2
Using Kirchhoff's Laws, solve for the current
through each resistor and the potential across in
each point.
R1
B
A
- E1
E1 = 4 V
€2 = 12 V
R1 = 30
R2 = 20
R3 = 30
Note: Input only one (1) decimal place in your
answer.
the answer is in whole number, then
do not write any decimal. Make sure to have
accurate answers. Do not forget the unit and no
spaces between characters. For the potential,
answer in whole numbers.
11 =
12 =
13 =
VA =
VB =
VC =
VD =
VE =
Next
Transcribed Image Text:3:33 D ONIal al 53% GenPhy2 Fourth Quarter Exam Part 2 Using Kirchhoff's Laws, solve for the current through each resistor and the potential across in each point. R1 B A - E1 E1 = 4 V €2 = 12 V R1 = 30 R2 = 20 R3 = 30 Note: Input only one (1) decimal place in your answer. the answer is in whole number, then do not write any decimal. Make sure to have accurate answers. Do not forget the unit and no spaces between characters. For the potential, answer in whole numbers. 11 = 12 = 13 = VA = VB = VC = VD = VE = Next
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