a.) The total resistance of the circuit isohms.(a) 67.647(b) 87.527(c) 96.673(d) 117.647b.) The total current isamperes.(a) 0.68(b) 0.46(c) 0.54(d ) 0.22c.) The power dissipation of R2 iswatts.(a) 9.2(b) 10.12(c) 4.84(d) 6.8 R1R42020R8:4ΩR5R268 VR630R920R3R750R10FIG. 1

Answered: Image /qna-images/answer/a7f7dd1d-2839-49bf-b5ec-7d24660518a1.jpg

Answered: R1 R4 20 20 R5 R8 40 R2 80 68 V R6 R9…

Engineering

Electrical Engineering

R1 R4 20 20 R5 R8 40 R2 80 68 V R6 R9 20 R3 R7 R10 FIG. 1

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Concept explainers

Current Division Method

The generalized current divider formula is given by the following relation below,

Question

a.) The total resistance of the circuit is
ohms.
(a) 67.647
(b) 87.527
(c) 96.673
(d) 117.647
b.) The total current is
amperes.
(a) 0.68
(b) 0.46
(c) 0.54
(d ) 0.22
c.) The power dissipation of R2 is
watts.
(a) 9.2
(b) 10.12
(c) 4.84
(d) 6.8

R1
R4
20
20
R8
:4Ω
R5
R2
68 V
R6
30
R9
20
R3
R7
50
R10
FIG. 1

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