R1 = 2.2 mm%3Dk2R2Thickness =R2 -R1= 1.1mmAirR1To=V = m/sVelocity v= 4.51 m/sklIgenL= 111Air Properties:kair = 0.0263 W/m.K, Vair = 15.89 × 10-6 m²/s,Prair = 0.707k2 = 1.23 W/m.K,Air (To= 25 °C) passes at velocity, V m/s , in across flow around the rod.The outer surface temperature, T2= (81CHeat is generated in a rod (R1, kı = 4 w/m.K), according to311I gen (r) = q0 (1-5) "W/m³", qo:constant valueR11. What is temperature distribution inside the rod in-terms of “heat generation:qo, surface temperature: T1, thermal conductivity: kı, R1 and r "2. What is the convective heat transfer coefficient (W/m².K) at R2, heat transfer rate(W), the temperature at the rod surface, T1, “C", the heat generation constant , qo"W/m3" and the maximum temperature in the rod ""C".

Name: R1 = 2.2 mm%3Dk2R2Thickness =R2 -R1= 1.1mmAirR1To=V = m/sVelocity v=
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Description: R1 = 2.2 mm%3Dk2R2Thickness =R2 -R1= 1.1mmAirR1To=V = m/sVelocity v= 4.51 m/sklIgenL= 111Air Properties:kair = 0.0263 W/m.K, Vair = 15.89 × 10-6 m²/s,Prair = 0.707k2 = 1.23 W/m.K,Air (To= 25 °C) passes at velocity, V m/s , in across flow around the

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Answered: R1 = 2.2 mm k2 R2 Thickness =R2 -R1=…

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R1 = 2.2 mm k2 R2 Thickness =R2 -R1= 1.1mm Air R1 Velocity v = 4.51 m/s V= m/s kl Igen L= 111 %3D Air Properties: kair = 0.0263 W/m.K, Vair = 15.89 × 10-6 m²/s, Prair = 0.707 k2 = 1.23 W/m.K,

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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