R P In the figure above a semi-infinite nonconducting rod (that is, infinite in one direction only) has uniform linear charge density X. NOTE: Use a standard ry coordinate system with a to the right and y upward, and express your answers to parts (a) and (b) in terms of R, A, and (a) Determine the x component of the electric field at point P. (b) Determine the y component of the electric field at point P. y 3= (c) Determine the counterclockwise angle 0 that the electric field makes with the +x axis. Unit= Choose one %3D

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In the figure above a semi-infinite nonconducting rod (that is, infinite
in one direction only) has uniform linear charge density A.
NOTE: Use a standard xy coordinate system with a to the right and y upward, and express
your answers to parts (a) and (b) in terms of R, X, and eg.
(a) Determine the x component of the electric field at point P.
(b) Determine the y component of the electric field at point P.
y =
(c) Determine the counterclockwise angle 0 that the electric field
makes with the +x axis.
Unit= Choose one ▼
Transcribed Image Text:P In the figure above a semi-infinite nonconducting rod (that is, infinite in one direction only) has uniform linear charge density A. NOTE: Use a standard xy coordinate system with a to the right and y upward, and express your answers to parts (a) and (b) in terms of R, X, and eg. (a) Determine the x component of the electric field at point P. (b) Determine the y component of the electric field at point P. y = (c) Determine the counterclockwise angle 0 that the electric field makes with the +x axis. Unit= Choose one ▼
Expert Solution
Step 1

Assume infinitesimal section of length dx of the rod at a distance x from the left end contain charge dq=λdx

Let this infinitesimal section of length dx is at a distance r from the point P.

The magnitude of electric field due to this section at point P is

dE=kdqr2=kλdxr2

 

 

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