R is the resultant of the four forces A, B, C, and D. Find the magnitude of the angle θ and the magnitude of C.
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R is the resultant of the four forces A, B, C, and D. Find the magnitude of the angle θ
and the magnitude of C.
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- Find the resultant force R of the following forces and its angle with the x-axis? F2=600N Fi=2i+5j N 3.317 65° F3=100N F4=250NA man pushing a mop across a floor causes it to undergo two displacements. The first has a magnitude of 140 cm and makes an angle of 124° with the positive x axis. The resultant displacement has a magnitude of 139 cm and is directed at an angle of 36.0° to the positive x axis. Find the magnitude and direction of the second displacement. magnitude cm direction * (counterclockwise from the positive x-axis)F1 F2 Given that F1 825 N, F2 = 630 N, and a = 32° , determine the magnitude of the resultant force and its direction measured counterclockwise from the positive x axis. . The magnitude of the resultant force in N is (round to two decimal places) : N The direction of the resultant force in degrees is (round to two decimal places) : degrees
- Figure Q1a shows two cables attached to a half-ring anchor point as shown in Figure Q1a. Force F1 acts vertically with a force of 2170 N; and F2 acts at an angle 0 relative to the y-axis with a force of 1240 N. y F1 F2 Figure Q1a Cable Anchor PointFind the resultant of the following forces by component method: F sub 1 = 12 N, south ; F sub 2 = 24 N, 30° north of west; F sub 3 = 15 N, 75° south of west; and F sub 4 = 32 N, 50° south of east. Tabulate the horizontal and vertical components of each vector.Two ropes are attached to a tire on the ground. The first rope exerts a force of 205. N in a direction 14.9 degrees west of north. The second rope exerts a force of 362. N in a direction 27.6 degrees east of south. Find the magnitude (in N) of the net force on the tire
- Two horizontal forces F= 70NÎ + 20NĴ and F= -30NÎ + 40Nj, are pulled a 12 body that is stuck in a field. The forces pull the body producing the vector forces shown in the figure. Find the direction and magnitude of the horizontal component of a third force on the body that will make the vector sum of forces on the body equal to zero.Using the method of components, find the resultant of the following concurrent forces. Note: After solving for the Angle of the Resultant, you must then determine the Direction of the Resultant relative to Horizontal (positive x-axis) in a CCW (counter-clockwise direction). Sometimes the Direction of the Resultant may be the same as the Angle of the Resultant. However, you must always calculate both: the Angle of the Resultant (based on the Resultant triangle sketch) and then the Direction of the Resultant based on Horizontal (positive x-axis) in a CCW direction from horizontal.a force F1=315N acts in the first quadrant at an angle of 70 degress above the x axis, while a second force F2=210N acts in the third quadrant at an angle of 40 degrees below the x axis. What is the magnitude of the resultant of these two forces. What is the direction (theta) of the resultant ?