(р - Е(Ф) р- Е(р) p - E(p) P(p < 0.60) = P 0.6-0.7 = P(Z< 0.0648, = P(Z <-1.543) = Z < 1.543 = 1- 0.9385 = 0.0615
(р - Е(Ф) р- Е(р) p - E(p) P(p < 0.60) = P 0.6-0.7 = P(Z< 0.0648, = P(Z <-1.543) = Z < 1.543 = 1- 0.9385 = 0.0615
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
100%
An exam consists of 50 multiple-choice questions. Based on how much you studied, for any given question, you think you have a
-
- If truly p = 0.7, would it be very surprising if you got correct answers on only 60% of the questions? Justify your answer by using the
normal distribution to approximate the probability of a sample proportion of 0.6 or less.
- If truly p = 0.7, would it be very surprising if you got correct answers on only 60% of the questions? Justify your answer by using the
The correct answer to this question is 0.0618. However, when I calculate the answer I keep getting 0.0615 using normalcdf(-1099,1.543,0,1). I have included a photo of my calculations. Please share with me what I am doing wrong when calculating this problem. Thank you!
![(р - Е(Ф) р- Е(р)
p - E(p)
P(p < 0.60) = P
0.6-0.7
= P(Z<
0.0648,
= P(Z <-1.543)
= Z < 1.543
= 1- 0.9385
= 0.0615](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2be4efe6-02a6-4a12-81ad-27e46b66d7a4%2Ff4014fec-3258-4541-8ff9-79ade67a5bbd%2Fhjz69q.png&w=3840&q=75)
Transcribed Image Text:(р - Е(Ф) р- Е(р)
p - E(p)
P(p < 0.60) = P
0.6-0.7
= P(Z<
0.0648,
= P(Z <-1.543)
= Z < 1.543
= 1- 0.9385
= 0.0615
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