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R A. 2R t. 20 Which spherical Gaussian surface has the larger electric flux? O Surface A O Surface B O They have the same flux. O Not enough information to tell. B.

R A. 2R t. 20 Which spherical Gaussian surface has the larger electric flux? O Surface A O Surface B O They have the same flux. O Not enough information to tell. B.

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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The image presents a question about electric flux through two spherical Gaussian surfaces. Here's a detailed transcription and explanation: ### Diagram Description: 1. **Surface A:** - A small circle labeled `A` with radius `R`. - Inside it, there is a positive charge, `+Q`. 2. **Surface B:** - A larger circle labeled `B` with radius `2R`. - Inside it, there is a positive charge, `+2Q`. ### Question: **Which spherical Gaussian surface has the larger electric flux?** ### Options: - Surface A - Surface B - They have the same flux. - Not enough information to tell. The diagrams show two different Gaussian surfaces with charges inside, posing a conceptual question on the electric flux across each surface, as per Gauss's law.
Transcribed Image Text:The image presents a question about electric flux through two spherical Gaussian surfaces. Here's a detailed transcription and explanation: ### Diagram Description: 1. **Surface A:** - A small circle labeled `A` with radius `R`. - Inside it, there is a positive charge, `+Q`. 2. **Surface B:** - A larger circle labeled `B` with radius `2R`. - Inside it, there is a positive charge, `+2Q`. ### Question: **Which spherical Gaussian surface has the larger electric flux?** ### Options: - Surface A - Surface B - They have the same flux. - Not enough information to tell. The diagrams show two different Gaussian surfaces with charges inside, posing a conceptual question on the electric flux across each surface, as per Gauss's law.
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