rー а) As per bartleby guideline I can solve only one question.(8) if you want other solution pls reupload. Step2 b) Solution: fix) = x2 + x + 1, g(x) = x - 3, (f - g)(x) = ? fx) = x2 + x + 1 g(x) = x - 3 Now (f- g)(x) = fXx) - g(x) - (x2 • x + 1) - x - 3)

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Question
4G, 4G
il Rul 11:17 30
A YO), 4G 36% O
KB/s
LTÉ1
v p-
a)
As per bartleby guideline I can solve
only one question.(8) if you want
other solution pls reupload.
Step2
b)
Solution:
+ x + 1, g(x) = x - 3, (f - g)(x) = ?
fix) = x2 + x + 1
g(x) %3 х - 3
Now (f- g)(x)
= fAx) - g(x)
- (2-x+1)- «
+ X +1]- (x - 3)
%3D
= x² + x + 1 - x + 3
%3D
= x2 + 4
Transcribed Image Text:4G, 4G il Rul 11:17 30 A YO), 4G 36% O KB/s LTÉ1 v p- a) As per bartleby guideline I can solve only one question.(8) if you want other solution pls reupload. Step2 b) Solution: + x + 1, g(x) = x - 3, (f - g)(x) = ? fix) = x2 + x + 1 g(x) %3 х - 3 Now (f- g)(x) = fAx) - g(x) - (2-x+1)- « + X +1]- (x - 3) %3D = x² + x + 1 - x + 3 %3D = x2 + 4
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