Solve iv and v only 3:16Instagram=0.62The capacitive reactance of the circuit can becalculated as:Xe300x 400x 10-6=8, 332Therefore, the inductive and capacitivereactance of the given circuit is 0.6 and 8.33ohm respectively.Part (ii).The rms value of the source is:325Vrms==229. 81 voltThe angle of the source is 0 degree, in phasorform it can be written as:Vphasor=Vrms4(angle)=229. 8120" voltTherefore, in phasor form the voltage can bewritten as 229. 8120° Volt.Part (iii).The total impedance of the above circuit can becalculated as:Zr=(R series jX1,) parallel (-jXc)=(3+ j0. 6) parallel (-j8. 33)(3+j0.6) x (- j8.33)(3+j0.6) + (- j8.33)=(3.028 – j0. 528)? R = 3 Nv-(t) = 325 cos 300t VC = 400 µFV.L = 2 mHFigure Q1By referring to Figure Q1, answer the following questions.i.Find the respective reactance of the inductor, XL, and capacitor, Xc.(marks)ii.Convert the voltage source from time domain, vs(t), to phasor domain, Vs. (The phasordomain needs to be in r.m.s).ii.Find the total impedance of the circuit.iv.Find vz(t) and iL(t) using Mesh analysis. (Show answer in peak value).Sketch the phasor diagram of VL and IL.V.

Given: Circuit elements are known Supply voltage is given Calculate: voltage, current, impedance in…

R = 3 N v.(t) = 325 cos 300t V C = 400 µF IL VL L = 2 mH Figure Q1 By referring to Figure Q1, answer the following questions. i. Find the respective reactance of the inductor, XL, and capacitor, Xc. marks) ii. Convert the voltage source from time domain, vs(t), to phasor domain, Vs. (The phasor domain needs to be in r.m.s). iii. Find the total impedance of the circuit. iv. Find vL(t) and iL(t) using Mesh analysis. (Show answer in peak value). Sketch the phasor diagram of VL and IL. V.

R = 3 N v.(t) = 325 cos 300t V C = 400 µF IL VL L = 2 mH Figure Q1 By referring to Figure Q1, answer the following questions. i. Find the respective reactance of the inductor, XL, and capacitor, Xc. marks) ii. Convert the voltage source from time domain, vs(t), to phasor domain, Vs. (The phasor domain needs to be in r.m.s). iii. Find the total impedance of the circuit. iv. Find vL(t) and iL(t) using Mesh analysis. (Show answer in peak value). Sketch the phasor diagram of VL and IL. V.

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

See similar textbooks

Similar questions

arm resistance of wheatstone bridge are. r1=200ohm r2=400ohm r3=500ohm r4=600ohm input is e=5v find the bridge output voltage
Problem 2: Draw block diagram V1 - input V2 - output R2 V2 VI
Answer in typing format please ASAP
Determine the output voltage in V when R1=9 kohm, R3=6 kohm, R5=13 k-ohm, R7=102 ohms, Reference Voltage of 2.5V, and input Voltage Vi=2.545 V. VPOS D R3 R5 REF R1 VNEG VNEG U1 R7 VNEG D U3 R2 VPOS D R4 R6 SENSOR VPOS D
Answers can be found at www.pearsonhighered.com/floyd. 1. The JFET is (a) a unipolar device (b) a voltage-controlled device (c) a current-controlled device (d) answers (a) and (c) (e) answers (a) and (b) 2. The channel of a JFET is between the (a) gate and drain (b) drain and source (c) gate and source (d) input and output 3. A JFET always operates with (a) the gate-to-source pn junction reverse-biased (b) the gate-to-source pn junction forward-biased (c) the drain connected to ground (d) the gate connected to the source 4. For VGs = 0 V, the drain current becomes constant when Vps exceeds (a) cutoff (b) VDD (c) Vp (d) 0 V 5. The constant-current region of a FET lies between (a) cutoff and saturation (b) cutoff and pinch-off (c) 0 and Ipss (d) pinch-off and breakdown 6. Ipss is (a) the drain current with the source shorted (b) the drain current at cutoff (c) the maximum possible drain current (d) the midpoint drain current 7. Drain current in the constant-current region increases when…
I need the answer as soon as possible
20v Ra R₁=52 = A) RTOTAL = B) I TOTAL = C) VTOTAL = D) R67 E) V³ H R₂ = 5 R3-22 R5=45² R6 = 3 R₁ = 252 R7 = 32
- Find Equivalent resistance of the circuit - Find the current through R5 - Find the voltage drop across R5 - Find the voltage drop across R4
Please solve within 30 minutes Show all the steps
What will be the count after 21 clock pulses?
?Calculate the current across the RI R1=50 R2=100 R3=150 V=120v R1 R2 R3