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R 100 kM 0,01'µF 0.022µF 10 k 5020° V f= 100 Hz R2 47 kM 820° f= 20 kHz 470 pF 470 pF (a) (b) 680 N 1000 pF C2 0.001 µF C, ο.0022 μ F 520° f= 100 kHz R2 1.2 k2 R3 1800 N

R 100 kM 0,01'µF 0.022µF 10 k 5020° V f= 100 Hz R2 47 kM 820° f= 20 kHz 470 pF 470 pF (a) (b) 680 N 1000 pF C2 0.001 µF C, ο.0022 μ F 520° f= 100 kHz R2 1.2 k2 R3 1800 N

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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6- find the impedience Z in following circuits

R C2 R 100 kN 0.01'µF 0.022 µF 10 kN 5020° V f= 100 Hz R2 47 kM 820° f= 20 kHz C2 470 pF 470 pF (a) (b) 680 N 1000 pF 0.001 µF 0.0022 μ F 5220° f= 100 kHz R2 1.2 kN R3 1800 2
Transcribed Image Text:R C2 R 100 kN 0.01'µF 0.022 µF 10 kN 5020° V f= 100 Hz R2 47 kM 820° f= 20 kHz C2 470 pF 470 pF (a) (b) 680 N 1000 pF 0.001 µF 0.0022 μ F 5220° f= 100 kHz R2 1.2 kN R3 1800 2
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