Quiz 1: Locate the centroid of the shaded area below and calculate the moment of inertia with respect to the axis a-a. a a -X² = 9y 3 m 6 m 6 m 3 m,
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A: By perpendicular axis theorem a) I =mr2/2 b) I = mr2/4 c) I = (2/3)mr2 d) I = (2/5)mr2
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Q: Part A Determine the moment of inertia of the shaded area about the x axis. Take that a = 3.6 in.…
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A: Simple problem of Moment of Inertia. Please have a good look
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A: The first option is correct.
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