Quinn lan Mark Brayden Tony Joseph Wade Gabriel Warren Evan Brendan Garrett Chad Jesse Nate Blake Diego Kevin Chase Tevin Justin Shaun Keegan Collin Ricky Kyle Jose Roberto Todd Shane Tristan Trey Damien Matt Darius Alex Jaime Brian Deandre Cameron Tom Manuel Ahmed Micah Eduardo Sergio Skyler Aidan Devonte Santos James Dylan Wyatt Roy Sam Omar Devante Caleb Juwan Chris Ricardo Zach Gregory Donald Juan Spencer Travis Colton Francisco Logan Danny Paul Andres Ken Demetrius Bill Isaac Jeremy Aaron Taylor Marcus Salvador Landon Jared Gerardo Arturo Dustin Austin Trent Luis or Trevor Randall Josh Antonio Carlos Armando Alfonso Cesar Chance Conner Use the random sample in the above table to test the claim that more than 5% of male names start with the letter "A". Use a = 0.05. 1. To confirm that the sample is large enough, there must be at least 5 successes and 5 failures, We are okay here, since there are mostly failures, and there are successes. The hypotheses are: O Ho:p <0.05; Ha:p > 0.05 O Ho:u 0.05; Ha:u < 0.05 O Ho:p 0.05; Ha:p 0.05 O Ho:p 2 0.05; Ha:p < 0.05 O Ho:u < 0.05; Ha: u > 0.05 Ho:u 0.05; Ha:u 0.05 MacBook Air

Quinn lan Mark Brayden Tony Joseph Wade Gabriel Warren Evan Brendan Garrett Chad Jesse Nate Blake Diego Kevin Chase Tevin Justin Shaun Keegan Collin Ricky Kyle Jose Roberto Todd Shane Tristan Trey Damien Matt Darius Alex Jaime Brian Deandre Cameron Tom Manuel Ahmed Micah Eduardo Sergio Skyler Aidan Devonte Santos James Dylan Wyatt Roy Sam Omar Devante Caleb Juwan Chris Ricardo Zach Gregory Donald Juan Spencer Travis Colton Francisco Logan Danny Paul Andres Ken Demetrius Bill Isaac Jeremy Aaron Taylor Marcus Salvador Landon Jared Gerardo Arturo Dustin Austin Trent Luis or Trevor Randall Josh Antonio Carlos Armando Alfonso Cesar Chance Conner Use the random sample in the above table to test the claim that more than 5% of male names start with the letter "A". Use a = 0.05. 1. To confirm that the sample is large enough, there must be at least 5 successes and 5 failures, We are okay here, since there are mostly failures, and there are successes. The hypotheses are: O Ho:p <0.05; Ha:p > 0.05 O Ho:u 0.05; Ha:u < 0.05 O Ho:p 0.05; Ha:p 0.05 O Ho:p 2 0.05; Ha:p < 0.05 O Ho:u < 0.05; Ha: u > 0.05 Ho:u 0.05; Ha:u 0.05 MacBook Air

Name: Joseph BraydenTonyQuinnlanMarkWadeGabrielWarrenEvanBrendanGarrettChad
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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Topic Video

Question

Joseph Brayden
Tony
Quinn
lan
Mark
Wade
Gabriel
Warren
Evan
Brendan
Garrett
Chad
Jesse
Nate
Chase
Tevin
Justin
Diego
Blake
Ricky
Keegan
Collin
Кyle
Kevin
Shaun
Jose
Roberto
Todd
Shane
Tristan
Trey
Damien
Matt
Darius
Alex
Jaime
Brian
Deandre
Cameron
Tom
Manuel
Ahmed
Micah
Eduardo
Aidan
Devonte
Santos
Sergio
Skyler
James
Dylan
Wyatt
Roy
ne
Sam
Omar
Devante
Caleb
Juwan
Chris
Ricardo
Zach
Gregory
Donald
Juan
Spencer
Andres
Travis
Colton
Francisco
Logan
Danny
Paul
Ken
Demetrius
Bill
Isaac
Jeremy
Marcus Salvador
Aaron
Taylor
Landon
Jared
Gerardo
Arturo
Dustin
Austin
Trent
Luis
octor
Trevor
Randall
Josh
Antonio
Carlos
Armando
Alfonso
Cesar
Chance
Conner
Use the random sample in the above table to test the claim that more than 5% of male names start with
the letter "A".
Use a = 0.05.
1. To confirm that the sample is large enough, there must be at least 5 successes and 5 failures. We are
okay here, since there are mostly failures, and there are
successes.
The hypotheses are:
О Но:р <0.05; На:р > 0.05
О Но: 2 0.05%;B На: и <0.05
O Ho:p = 0.05; Ha:p # 0.05
O Ho:p 2 0.05; Ha:p < 0.05
O Ho:u <0.05; Ha:u > 0.05
O Ho:u = 0.05; Ha:µ # 0.05
MacBook Air
80
F3
000
F2
F4
11
F8
F5
F6
F7
F9
&
*

O Ho:µ = 0.05; Ha:µ 0.05
2. This is a O leftO twoO right tailed test and the distribution used is
OT since o not known
OZ since testing a proportion
OZ since o known
The Degrees of Freedom are
O 9
O 100
ON/A since this is a Z-test
3. The STS (round to 3 decimals) is:
The P-value (round to 4 decimals) is:
4. The decision at a = 0.05 is:
O Do not reject Ho since P > a
ODo not reject Ho since P<a
O Reject Ho since P < a
O Reject Ho since P > a
The conclusion is:
O There is insufficient evidence to conclude that the proportion is more than 0.05
O There is sufficient evidence to conclude that the proportion is not more than 0.05
O There is insufficient evidence to conclude that the proportion is not more than 0.05
O There is sufficient evidence to conclude that the proportion is more than 0.05
MacBook Air
F2
000
600
F4
F3
11
F5
F6
F7
%23
3

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