Quinn lan Mark Brayden Tony Joseph Wade Gabriel Warren Evan Brendan Garrett Chad Jesse Nate Blake Diego Kevin Chase Tevin Justin Shaun Keegan Collin Ricky Kyle Jose Roberto Todd Shane Tristan Trey Damien Matt Darius Alex Jaime Brian Deandre Cameron Tom Manuel Ahmed Micah Eduardo Sergio Skyler Aidan Devonte Santos James Dylan Wyatt Roy Sam Omar Devante Caleb Juwan Chris Ricardo Zach Gregory Donald Juan Spencer Travis Colton Francisco Logan Danny Paul Andres Ken Demetrius Bill Isaac Jeremy Aaron Taylor Marcus Salvador Landon Jared Gerardo Arturo Dustin Austin Trent Luis or Trevor Randall Josh Antonio Carlos Armando Alfonso Cesar Chance Conner Use the random sample in the above table to test the claim that more than 5% of male names start with the letter "A". Use a = 0.05. 1. To confirm that the sample is large enough, there must be at least 5 successes and 5 failures, We are okay here, since there are mostly failures, and there are successes. The hypotheses are: O Ho:p <0.05; Ha:p > 0.05 O Ho:u 0.05; Ha:u < 0.05 O Ho:p 0.05; Ha:p 0.05 O Ho:p 2 0.05; Ha:p < 0.05 O Ho:u < 0.05; Ha: u > 0.05 Ho:u 0.05; Ha:u 0.05 MacBook Air

Quinn lan Mark Brayden Tony Joseph Wade Gabriel Warren Evan Brendan Garrett Chad Jesse Nate Blake Diego Kevin Chase Tevin Justin Shaun Keegan Collin Ricky Kyle Jose Roberto Todd Shane Tristan Trey Damien Matt Darius Alex Jaime Brian Deandre Cameron Tom Manuel Ahmed Micah Eduardo Sergio Skyler Aidan Devonte Santos James Dylan Wyatt Roy Sam Omar Devante Caleb Juwan Chris Ricardo Zach Gregory Donald Juan Spencer Travis Colton Francisco Logan Danny Paul Andres Ken Demetrius Bill Isaac Jeremy Aaron Taylor Marcus Salvador Landon Jared Gerardo Arturo Dustin Austin Trent Luis or Trevor Randall Josh Antonio Carlos Armando Alfonso Cesar Chance Conner Use the random sample in the above table to test the claim that more than 5% of male names start with the letter "A". Use a = 0.05. 1. To confirm that the sample is large enough, there must be at least 5 successes and 5 failures, We are okay here, since there are mostly failures, and there are successes. The hypotheses are: O Ho:p <0.05; Ha:p > 0.05 O Ho:u 0.05; Ha:u < 0.05 O Ho:p 0.05; Ha:p 0.05 O Ho:p 2 0.05; Ha:p < 0.05 O Ho:u < 0.05; Ha: u > 0.05 Ho:u 0.05; Ha:u 0.05 MacBook Air

Name: Joseph BraydenTonyQuinnlanMarkWadeGabrielWarrenEvanBrendanGarrettChad
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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Use the random sample in the above table to test the claim that more than 5% of male names start with
the letter "A".
Use a = 0.05.
1. To confirm that the sample is large enough, there must be at least 5 successes and 5 failures. We are
okay here, since there are mostly failures, and there are
successes.
The hypotheses are:
О Но:р <0.05; На:р > 0.05
О Но: 2 0.05%;B На: и <0.05
O Ho:p = 0.05; Ha:p # 0.05
O Ho:p 2 0.05; Ha:p < 0.05
O Ho:u <0.05; Ha:u > 0.05
O Ho:u = 0.05; Ha:µ # 0.05
MacBook Air
80
F3
000
F2
F4
11
F8
F5
F6
F7
F9
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*

O Ho:µ = 0.05; Ha:µ 0.05
2. This is a O leftO twoO right tailed test and the distribution used is
OT since o not known
OZ since testing a proportion
OZ since o known
The Degrees of Freedom are
O 9
O 100
ON/A since this is a Z-test
3. The STS (round to 3 decimals) is:
The P-value (round to 4 decimals) is:
4. The decision at a = 0.05 is:
O Do not reject Ho since P > a
ODo not reject Ho since P<a
O Reject Ho since P < a
O Reject Ho since P > a
The conclusion is:
O There is insufficient evidence to conclude that the proportion is more than 0.05
O There is sufficient evidence to conclude that the proportion is not more than 0.05
O There is insufficient evidence to conclude that the proportion is not more than 0.05
O There is sufficient evidence to conclude that the proportion is more than 0.05
MacBook Air
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B 1 Team 2 DET 3 BOS 4 TEX 5 NYY 6 LAA 7 OAK 8 LAA 9 BOS 10 SEA 11 CWS 12 SEA 13 NYY 14 CLE 15 MIN 16 CWS 17 BAL 18 TEX 19 DET 20 TB 21 DET 22 23 с W 24 13 16 19 16 9 11 15 14 13 9 8 12 9 8 9 14 15 11 14 D L 5 7 7 8 10 9 12 9 14 9 10 10 7 13 12 17 10 9 10 9 E ERA 2.39 2.88 2.94 2.99 3.16 3.32 3.37 3.47 3.46 3.58 3.73 3.99 4.24 4.29 4.33 4.32 4.39 4.42 4.44 4.75 F G SO/IP HR/IP 1.00 0.09 0.91 0.10 0.92 0.06 0.96 0.07 0.80 0.07 0.71 0.06 0.78 0.11 0.94 0.10 0.95 0.08 0.52 0.09 1.01 0.10 0.81 0.13 0.53 0.15 0.45 0.79 0.62 0.10 0.11 0.13 0.83 0.16 0.88 0.15 0.56 0.13 0.57 0.09 H R/IP 0.28 0.33 0.39 0.37 0.38 0.43 0.41 0.40 0.41 0.44 0.43 0.52 0.48 0.55 0.52 0.53 0.51 0.51 0.52 0.57 I SUMMARY OUTPUT J Regression Statistics Multiple R R Square Adjusted R Square Standard Error Observations ANOVA Regression Residual Total Intercept SO/IP HR/IP K 0.764808258 0.584931672 0.536100104 0.053761887 df 20 L M MS N O F Significance F SS 2 0.069244211 0.034622106 11.97856 0.000567566 17 0.049135789…
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