Questions Phases and Eclipses Problem 9 15. 16. 17. 18. 19. - O O Use the small-angle formula to calculate the angular diameter of Earth as seen from the Moon. (Note: The linear diameter of Earth is 12,700 km; the average distance between the Moon and Earth is 384,000 km; the small-angle formula is angular diameter (in arc seconds) 2.06 x 105 a. About 0.9° or 3400 arc seconds. b. About 3.8° or 13,700 arc seconds. Oc. About 0.5° or 1700 arc seconds. d. About 1.9 or 6800 arc seconds. 0 Icon Key linear diameter distance
Questions Phases and Eclipses Problem 9 15. 16. 17. 18. 19. - O O Use the small-angle formula to calculate the angular diameter of Earth as seen from the Moon. (Note: The linear diameter of Earth is 12,700 km; the average distance between the Moon and Earth is 384,000 km; the small-angle formula is angular diameter (in arc seconds) 2.06 x 105 a. About 0.9° or 3400 arc seconds. b. About 3.8° or 13,700 arc seconds. Oc. About 0.5° or 1700 arc seconds. d. About 1.9 or 6800 arc seconds. 0 Icon Key linear diameter distance
Applications and Investigations in Earth Science (9th Edition)
9th Edition
ISBN:9780134746241
Author:Edward J. Tarbuck, Frederick K. Lutgens, Dennis G. Tasa
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apter 3: Sample Assignment
Assignment: Chapter 3: Sample Assignment
Questions Phases and Eclipses Problem 9
15.
16.
17.
18.
19.
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384,000 km; the small-angle formula is
angular diameter (in arc seconds)
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Use the small-angle formula to calculate the angular diameter of Earth as seen from the Moon. (Note: The linear diameter of Earth is
12,700 km; the average distance between the Moon and Earth is
O b. About
3.8° or
13,700 arc seconds.
A
a. About
0.9° or
3400 arc seconds.
D
Od. About
1.9° or
6800 arc seconds.
N
c. About
0.5° or
1700 arc seconds.
Icon Key
10
Phases and Eclipses Problem 9
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Phases and Eclipses Problem 1
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b. 7 days. It depends on the synodic period.
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Phases and Eclipses Problem 1
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