Questions (must be typed and attached) 1. Fully describe the images created by diverging lenses. 2. Can the image created by a diverging lens be projected onto a screen? Explain why or why not?
Questions (must be typed and attached) 1. Fully describe the images created by diverging lenses. 2. Can the image created by a diverging lens be projected onto a screen? Explain why or why not?
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![Questions (must be typed and attached)
1. Fully describe the images created by diverging lenses.
2. Can the image created by a diverging lens be projected onto a screen? Explain why or why
not?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4a6e4794-5644-431d-9e96-b37fbaf0b60a%2F2705c5da-944c-4d09-829c-7463f6762561%2Ffohzvcg_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Questions (must be typed and attached)
1. Fully describe the images created by diverging lenses.
2. Can the image created by a diverging lens be projected onto a screen? Explain why or why
not?
![$
-12
8:41
-12
Step3
c)
Object
Step4
d)
Far
object
Close
object
Concave Lens: do any
-10
Problem Object
Image Characteristics
Virtual Image
Upright
|hi| < |ho|
0> di > f
Concave Lens: do= any
Focus
Image Characteristics
Virtual Image
Upright
|hi| < |ho|
0> di > f
distances
(m)
11
Focus
2
Object
height
h (m)
3
Image
2
Q
Image Image
distance height
s' (m) h' (m)
-3.88 1.06
-1.5
1.5
?
do 11
ho = 3
M = 0.35
7=-6.
f = -6
do = 2
ho = 2
M = 0.75
m=
Magnification,
0.35
. 5G
0.75
Four
√x
di = -3.88
hi 1.06
Focus
*
di = -1.5
hi= 1.5
Magnification,
m=!
==
0.35
0.75
8](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4a6e4794-5644-431d-9e96-b37fbaf0b60a%2F2705c5da-944c-4d09-829c-7463f6762561%2F6fk5enj_processed.jpeg&w=3840&q=75)
Transcribed Image Text:$
-12
8:41
-12
Step3
c)
Object
Step4
d)
Far
object
Close
object
Concave Lens: do any
-10
Problem Object
Image Characteristics
Virtual Image
Upright
|hi| < |ho|
0> di > f
Concave Lens: do= any
Focus
Image Characteristics
Virtual Image
Upright
|hi| < |ho|
0> di > f
distances
(m)
11
Focus
2
Object
height
h (m)
3
Image
2
Q
Image Image
distance height
s' (m) h' (m)
-3.88 1.06
-1.5
1.5
?
do 11
ho = 3
M = 0.35
7=-6.
f = -6
do = 2
ho = 2
M = 0.75
m=
Magnification,
0.35
. 5G
0.75
Four
√x
di = -3.88
hi 1.06
Focus
*
di = -1.5
hi= 1.5
Magnification,
m=!
==
0.35
0.75
8
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