questions correct. Using a = 0.05, perform a chi-square test to determine if the number of correct answers per student follows the binomial probability distribution. Click the icon to view the data table. What is the null hypothesis, Ho? O A. Ho: The mean number of correct answers per student is not equal to 0. OB. Ho: The number of correct answers per student follows the binomial probability distribution. OC. Ho: The number I correct answers per student does not follow the binomial probability distribution. O D. Ho: The mean number of correct answers per student is equal to 0. What is the alternative hypothesis, H,? CA. H1: The number of correct answers per student does not follow the binomial probability distribution. O B. H,: The number of correct answers per student follows the binomial probability distribution. OC. H,: The mean number of correct answers per student is not equal to 0. O D. H,: The mean number of correct answers per student is equal to 0. What is the probability f success, p, for this binomial distribution? p= (Type an integer or a decimal.) Calculate the test statistic. x2 = (Round to two decimal places as needed.) Determine the p-value for the test statistic. p-value = (Round to three decimal places as needed.)

MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
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Question
State the appropriate conclusion.
(1)
Ho. At the 5% significance level, there (2)
enough evidence to conclude that the distribution of the number of correct answers per student does not follow the claimed, or expected, distribution.
1:
Number of Correct
Answers per Student
Frequency
4
1
6
2
10
3
10
4
10
Total
40
(1) O Do not reject
(2)
O is
O Reject
O is not
Transcribed Image Text:State the appropriate conclusion. (1) Ho. At the 5% significance level, there (2) enough evidence to conclude that the distribution of the number of correct answers per student does not follow the claimed, or expected, distribution. 1: Number of Correct Answers per Student Frequency 4 1 6 2 10 3 10 4 10 Total 40 (1) O Do not reject (2) O is O Reject O is not
3. Suppose a teacher gives her statistics class a four-question, multiple-choice quiz at the beginning of the semester to measure how well prepared they were for the class. The accompanying table shows the number of students who had 0, 1, 2, 3 and 4
questions correct. Using a = 0.05, perform a chi-square test to determine if the number of correct answers per student follows the binomial probability distribution.
Click the icon to view the data table.
What is the null hypothesis, Ho?
O A. Ho: The mean number of correct answers per student is not equal to 0.
OB. Ho: The number of correct answers per student follows the binomial probability distribution.
O C. Ho: The number of correct answers per student does not follow the binomial probability distribution.
O D. Ho: The mean number of correct answers per student is equal to 0.
What is the alternative hypothesis, H, ?
O A. H,: The number of correct answers per student does not follow the binomial probability distribution.
O B. H,: The number of correct answers per student follows the binomial probability distribution.
O C. H,: The mean number of correct answers per student is not equal to 0.
O D. H,: The mean number of correct answers per student is equal to 0.
What is the probability of success, p, for this binomial distribution?
p=
(Type an integer or a decimal.)
Calculate the test statistic.
(Round to two decimal places as needed.)
Determine the p-value for the test statistic.
p-value =
(Round to three decimal places as needed.)
State the appropriate conclusion.
(1)
Họ. At the 5% significance level, there (2)
enough evidence to conclude that the distribution of the number of correct answers per student does not follow the claimed, or expected, distribution.
Transcribed Image Text:3. Suppose a teacher gives her statistics class a four-question, multiple-choice quiz at the beginning of the semester to measure how well prepared they were for the class. The accompanying table shows the number of students who had 0, 1, 2, 3 and 4 questions correct. Using a = 0.05, perform a chi-square test to determine if the number of correct answers per student follows the binomial probability distribution. Click the icon to view the data table. What is the null hypothesis, Ho? O A. Ho: The mean number of correct answers per student is not equal to 0. OB. Ho: The number of correct answers per student follows the binomial probability distribution. O C. Ho: The number of correct answers per student does not follow the binomial probability distribution. O D. Ho: The mean number of correct answers per student is equal to 0. What is the alternative hypothesis, H, ? O A. H,: The number of correct answers per student does not follow the binomial probability distribution. O B. H,: The number of correct answers per student follows the binomial probability distribution. O C. H,: The mean number of correct answers per student is not equal to 0. O D. H,: The mean number of correct answers per student is equal to 0. What is the probability of success, p, for this binomial distribution? p= (Type an integer or a decimal.) Calculate the test statistic. (Round to two decimal places as needed.) Determine the p-value for the test statistic. p-value = (Round to three decimal places as needed.) State the appropriate conclusion. (1) Họ. At the 5% significance level, there (2) enough evidence to conclude that the distribution of the number of correct answers per student does not follow the claimed, or expected, distribution.
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k= 5 categoris 

n = 40 tatal frequency 

 

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