>$2010each question.1. How much pure acid is in 250 mL of a 14% acid solution?250 (14)= 3535 Liters2. If $10,000 is invested for 1 yr at 3.5% simple interest, how much interest is earned?I = 10,000 (0.035) (1) = 350$3503. What is the monetary value of 283 nickels?283 (+05) = 14.1514.15B. Solve each problem.4. How many liters of a 10% alcohol solution must be mixed with 40 L of a 50% solution toobtain a 40% solution?20=-3x+16x (0-1) + 40 (0.5) =.40 (x+40)=-3x40x716-·lk0.1x + 20 =--1x33335. How many gallons of a fruit drink that is 50% real juice must be mixed with a fruit drinkthat is 20% real juice to obtain 12 gal of a fruit drink that is 40% real juice?-70x +2.4=480-2.4 -2.47 = 477.679-7.50 x + 20 (12-x) = 12 (40)• 50x+ 2.4 -- 20x = 4804-201+.20x#6000#9000AmountInvested (indollars)XX-2500x =16. Margaret won a prize for her work. She invested part of the money in a certificate ofdeposit at 2% and $3000 more than that amount in a bond paying 3%. Her annual interestincome was $390. How much did Margaret invest at each rate?amountx +3000Rate (as adecimal)rate0.020.030.080.02Due Date: August 23, 2023-160.02x +0.03(x+3000)=3900.02% 0.03x +90 = 3900.05x + 90 = 390-90-910.05x=3000.05x7. Jamal had $2500, some of which he deposited in a mutual fund account paying 8%. Therest he deposited in a money market account paying 2%. How much did he deposit in eachaccount if the total annual interest was $152?Interest for OneYear (in dollars)Interst peo fear0.08x0.02(x-2500)53-30.02x-160.03(x+3000)0.08 +0.02(x-2500) = 1520.08x+0.02x-50=1520.1x-50 = 152+50 +500₁1x = 2020.1x0.1Xis earnex=2020luti0.05kX=600

To determine the amount of the pure acid in 250 ml of a 14% acid solution.Note: Since the student…

Answered: question. 1. How much pure acid is in…

question. 1. How much pure acid is in 250 mL of a 14% acid solution? 250 (14) = 35 35 Liters 2. If $10,000 is invested for vn Due

17th Edition

ISBN:9780998625713

Author:Lynn Marecek, MaryAnne Anthony-Smith

Publisher:Lynn Marecek, MaryAnne Anthony-Smith

Chapter1: Foundations

Section1.2: Use The Language Of Algebra

Problem 179E: Car insurance Justin’s car insurance has a $750 deductible per incident. This means that he pays...

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