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question. 1. How much pure acid is in 250 mL of a 14% acid solution? 250 (14) = 35 35 Liters 2. If $10,000 is invested for vn Due

question. 1. How much pure acid is in 250 mL of a 14% acid solution? 250 (14) = 35 35 Liters 2. If $10,000 is invested for vn Due

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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> $2010 each question. 1. How much pure acid is in 250 mL of a 14% acid solution? 250 (14) = 35 35 Liters 2. If $10,000 is invested for 1 yr at 3.5% simple interest, how much interest is earned? I = 10,000 (0.035) (1) = 350 $350 3. What is the monetary value of 283 nickels? 283 (+05) = 14.15 14.15 B. Solve each problem. 4. How many liters of a 10% alcohol solution must be mixed with 40 L of a 50% solution to obtain a 40% solution? 20=-3x+16 x (0-1) + 40 (0.5) =.40 (x+40) =-3x 40x716 -·lk 0.1x + 20 = --1x 3333 5. How many gallons of a fruit drink that is 50% real juice must be mixed with a fruit drink that is 20% real juice to obtain 12 gal of a fruit drink that is 40% real juice? -70x +2.4=480 -2.4 -2.4 7 = 477.6 79 -7 .50 x + 20 (12-x) = 12 (40) • 50x+ 2.4 -- 20x = 480 4-201 +.20x #6000 #9000 Amount Invested (in dollars) X X-2500 x = 1 6. Margaret won a prize for her work. She invested part of the money in a certificate of deposit at 2% and $3000 more than that amount in a bond paying 3%. Her annual interest income was $390. How much did Margaret invest at each rate? amount x +3000 Rate (as a decimal) rate 0.02 0.03 0.08 0.02 Due Date: August 23, 2023 -16 0.02x +0.03(x+3000)=390 0.02% 0.03x +90 = 390 0.05x + 90 = 390 -90 -91 0.05x=300 0.05x 7. Jamal had $2500, some of which he deposited in a mutual fund account paying 8%. The rest he deposited in a money market account paying 2%. How much did he deposit in each account if the total annual interest was $152? Interest for One Year (in dollars) Interst peo fear 0.08x 0.02(x-2500) 53 -3 0.02x -16 0.03(x+3000) 0.08 +0.02(x-2500) = 152 0.08x+0.02x-50=152 0.1x-50 = 152 +50 +50 0₁1x = 202 0.1x 0.1X is earne x=2020 luti 0.05k X=600
Transcribed Image Text:> $2010 each question. 1. How much pure acid is in 250 mL of a 14% acid solution? 250 (14) = 35 35 Liters 2. If $10,000 is invested for 1 yr at 3.5% simple interest, how much interest is earned? I = 10,000 (0.035) (1) = 350 $350 3. What is the monetary value of 283 nickels? 283 (+05) = 14.15 14.15 B. Solve each problem. 4. How many liters of a 10% alcohol solution must be mixed with 40 L of a 50% solution to obtain a 40% solution? 20=-3x+16 x (0-1) + 40 (0.5) =.40 (x+40) =-3x 40x716 -·lk 0.1x + 20 = --1x 3333 5. How many gallons of a fruit drink that is 50% real juice must be mixed with a fruit drink that is 20% real juice to obtain 12 gal of a fruit drink that is 40% real juice? -70x +2.4=480 -2.4 -2.4 7 = 477.6 79 -7 .50 x + 20 (12-x) = 12 (40) • 50x+ 2.4 -- 20x = 480 4-201 +.20x #6000 #9000 Amount Invested (in dollars) X X-2500 x = 1 6. Margaret won a prize for her work. She invested part of the money in a certificate of deposit at 2% and $3000 more than that amount in a bond paying 3%. Her annual interest income was $390. How much did Margaret invest at each rate? amount x +3000 Rate (as a decimal) rate 0.02 0.03 0.08 0.02 Due Date: August 23, 2023 -16 0.02x +0.03(x+3000)=390 0.02% 0.03x +90 = 390 0.05x + 90 = 390 -90 -91 0.05x=300 0.05x 7. Jamal had $2500, some of which he deposited in a mutual fund account paying 8%. The rest he deposited in a money market account paying 2%. How much did he deposit in each account if the total annual interest was $152? Interest for One Year (in dollars) Interst peo fear 0.08x 0.02(x-2500) 53 -3 0.02x -16 0.03(x+3000) 0.08 +0.02(x-2500) = 152 0.08x+0.02x-50=152 0.1x-50 = 152 +50 +50 0₁1x = 202 0.1x 0.1X is earne x=2020 luti 0.05k X=600
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