Question What is the standard form of the equation of the parabola with the focus (-4,-6) and the directrix y = 4? Note: the directrix is of the form y = d, which tells us that the parabola opens vertically, and so the form of the parabola will be of the form (x − h)² = 4p(y – k). Use k and p to find the equation of the directrix, y = k - p. Select the correct answer below: O (x+4)= −20(y + 1)² ○ (y + 1) = −20(x+4)² ○ (x+4)² = −20(y+1) ○ (y + 1)² = -20(x+4) FEEDBACK SUBMIT

Intermediate Algebra
19th Edition
ISBN:9780998625720
Author:Lynn Marecek
Publisher:Lynn Marecek
Chapter11: Conics
Section11.2: Parabolas
Problem 11.38TI: Find the equation of the parabolic arch formed in the foundation of the bridge shown. Write the...
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I am unsure how to solve this. I have zero idea what a directrix is and I cannot find anything about it anywhere.

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What is the standard form of the equation of the parabola with the focus (-4,-6) and the directrix y = 4?
Note: the directrix is of the form y=d, which tells us that the parabola opens vertically, and so the form of the parabola
will be of the form (x − h)² = 4p(y – k). Use k and p to find the equation of the directrix, y = k — p.
Select the correct answer below:
○ (x+4)= −20(y + 1)²
○ (y + 1) | = −20(x+4)²
○ (x+4)² = −20(y+1)
○ (y + 1)² = −20(x+4)
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SUBMIT
Transcribed Image Text:Question What is the standard form of the equation of the parabola with the focus (-4,-6) and the directrix y = 4? Note: the directrix is of the form y=d, which tells us that the parabola opens vertically, and so the form of the parabola will be of the form (x − h)² = 4p(y – k). Use k and p to find the equation of the directrix, y = k — p. Select the correct answer below: ○ (x+4)= −20(y + 1)² ○ (y + 1) | = −20(x+4)² ○ (x+4)² = −20(y+1) ○ (y + 1)² = −20(x+4) FEEDBACK SUBMIT
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