Question Three An isosceles triangle can be constructed by joining the following coordinates on a Cartesian plane: A(2, 2), B(5, 11) and C(8, 2). BS, 11) A(2,2) CI8.2) a. Determine the equations of the straight lines joining the points of the triangle listed above.
Question Three An isosceles triangle can be constructed by joining the following coordinates on a Cartesian plane: A(2, 2), B(5, 11) and C(8, 2). BS, 11) A(2,2) CI8.2) a. Determine the equations of the straight lines joining the points of the triangle listed above.
Calculus: Early Transcendentals
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![Question Three
An isosceles triangle can be constructed by joining the following coordinates on a Cartesian plane:
A(2, 2), B(5, 11) and C(8, 2).
BS, 11)
A(2,2)
CI8.2)
a. Determine the equations of the straight lines joining the points of the triangle listed above.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3ce30394-723f-4504-a20a-97e6e559e50a%2Fe75393fa-7f7e-4db2-8e89-6fbde8562f59%2Ffqwq1bc9_processed.png&w=3840&q=75)
Transcribed Image Text:Question Three
An isosceles triangle can be constructed by joining the following coordinates on a Cartesian plane:
A(2, 2), B(5, 11) and C(8, 2).
BS, 11)
A(2,2)
CI8.2)
a. Determine the equations of the straight lines joining the points of the triangle listed above.
![b. State the base length and perpendicular height of the triangle and use these values to determine
its area.
c. State the integral(s) that would allow you to find the area of the isosceles triangle.
d. Show that the value of the integral(s) in part e is the same as the area found in part b.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3ce30394-723f-4504-a20a-97e6e559e50a%2Fe75393fa-7f7e-4db2-8e89-6fbde8562f59%2Fkj39o5t_processed.png&w=3840&q=75)
Transcribed Image Text:b. State the base length and perpendicular height of the triangle and use these values to determine
its area.
c. State the integral(s) that would allow you to find the area of the isosceles triangle.
d. Show that the value of the integral(s) in part e is the same as the area found in part b.
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