Question : suppose the average length of stay in a chronic disease hospital of certain type of patient is 65 days with a standard deviation of 15 days. if it is reasonable to assume an approximately normal distribution of length of stay. Find the probability that a randomly selected patient from this group will have a length of stay: A) less than 65 days? B) more than 50 days? C) find (a), if P(X

Q: Scores on the Wechsler Adult Intelligence Test are normally distributed with a mean of 100 and a…

A: Given:' Mean = μ=100 Standard deviation = σ= 10

Q: The mean height of an adult giraffe is 18 feet. Suppose that the distribution is normally…

A: Given,

Q: The time that a skier takes on a downhill course has a normal distribution with a mean of 12.a…

A: The objective of this question is to find the probability of a skier taking less than 10 minutes and…

Q: data from an assessment of a group of subjects is known to have a mean of 100 and a standard…

A: Suppose the variable of interest is x with mean  and the standard deviation of .

Q: Claim: The standard deviation of pulse rates of adult males is less than 10 bpm. For a random sample…

A: The objective of the question is to determine if the claim that the standard deviation of pulse…

Q: If four healthy adults are randomly selected, find the probability that their mean 25-OHD level is…

A: P(X<50)=0.2675 (from graph)

Q: set will be less than -8.5 percent in a given year? Use the NORMDIST function in Excel(R) to answer…

A: Answer The favorable cases [x] = - 8.50%The mean 6.6%The standard deviation = 16.5%

Q: nsurance companies know the risk of insurance is greatly reduced if the company insures not just one…

A: Given : For Joel X1 =51.1  &  standard deviation =13.4 For David X2=51.1 & standard…

Q: Service time for a customer coming through a checkout counter in a retail store is a random variable…

A:

Q: A population of normally distributed scores has a mean of 50 and standard deviation of 12.  What is…

A: Given information- Population mean, µ = 50 Population standard deviation, σ = 12 Sample size, n = 36…

Q: SAT scores in one state is normally distributed with a mean of 1523 and a standard deviation of 184.…

A:

Q: Let x be the number showing on a fair six-sided die. The distribution of x has a mean of 3.5 and a…

A: Central limit theorem:For iid random variables, Xi (i = 1, 2, …, n) with mean E(Xi) = µ and standard…

Q: A leading magazine reported at one time that the average number of weeks an individual is unemployed…

A:

Q: IQ scores follow an approximately Normal distribution with a mean of 100 and standard deviation of…

A: Population mean μ =100 Population standard deviation =15

Q: Suppose X is a normally distributed random variable with mean = 46 and st.deviation = 5 . Find a…

A:

Q: SAT scores in one state is normally distributed with a mean of 1532 and a standard deviation of 200.…

A: GivenMean(μ)=1532standard deviation(σ)=200sample size(n)=50

Q: Vehicle speeds at a certain highway location have a mean of 100 kmh and a standard deviation of 10…

A: Given,sample size(n)=25sample mean(x¯)=100standard deviation(σ)=10α=1-0.95=0.05α2=0.025Z0.025=1.96…

Q: A random variable is normally distributed with a mean of μ = 50 and a standard deviation of σ = 5.…

A: Given Mean(μ)=50standard deviation(σ)=5

Q: According to a study done by UCB students, the height for Martian adult males is normally…

A: Find the probability that the person is between 65.1 and 66.4 inches? Let X = height of the…

Q: Assume that a randomly selected subject is given a bone density test. Those test scores are normally…

A: Answer : From the given data, Suppose X denote the test scores with Mean (μ) =0 standard deviation…

Q: Assume that a randomly selected subject given a bone density test. Those test scores are normally…

A:

Q: The patient recovery time from a particular surgical procedure is normally distributed with a mean…

A: Given Data : Population Mean,μ = 4 Population Standard Deviation,σ = 1.5

Q: he level of nitrogen oxides (NOX) and nonmethane organic gas (NMOG) in the exhaust over the useful…

A: Given Data: Mean (μ)=85 Standard deviation (σ)=6 Variance (σ2)=36 Sample size(n)=16   Let X be the…

Q: Suppose the full score for our final exam is 200 points. Based on previous record, we know students…

A: Given that.   X~N( μ , ?)   μ=160  , ?=15  , n=25   Z-score =( x - μ )/?

Q: The distribution of raw scores on a chemistry final is approximately normal with mean of about 50…

A: Solution: Let X be the raw scores on a chemistry final. From the given information, X follows normal…

Q: On average, indoor cats live to 15 years old with a standard deviation of 2.7 years. Suppose that…

A: b.

Q: Annual food consumption survey shows that number of instant food meals consumed per month by…

A:

Q: Assume that the number of sick patient per day are normally distributed with a mean of 5000 and a…

A:

Q: Let x denote the time taken to run a road race. Supposex is approximately normally distributed with…

A: Ans: Given,   X ~ N(μ, σ)        Where  μ  = 190 minutes   and σ  = 21 minutes        Find  P( 219…

Q: Assume that adults have IQ scores that are normally distributed with a mean of μ=100and a standard…

A: From the provided information, Mean (µ) = 100 Standard deviation (σ) = 20 Let X be a random variable…

Q: Assume that adults have IQ scores that are normally distributed with mean of mu = 100 and a standard…

A:

Q: Americans receive an average of 16 Christmas cards each year. Suppose the number of Christmas cards…

A: Since you have asked multiple question, we will solve the first question for you. If you want any…

Q: Assume that adults have IQ scores that are normally distributed with a mean of μ=105 and a standard…

A:

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.