Question :- Suppose that of | -f1z) | = | on |2|=1. When is entire function and That_fR²) = C. 2². pona
Question :- Suppose that of | -f1z) | = | on |2|=1. When is entire function and That_fR²) = C. 2². pona
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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121=1. y han
pone
|- f₁2)| = |
Solt:
The
first-
on
analytic
If of has
Symmetry
infinity.
Zero
function
f is entire.
We
the paint
Again
Lam of (w)
Now t
in
So fiz)
| f₁₂) | = 1
Zero
f would have
using gymorely
Henle
Com
which
-
prove
ㅏ
<\ {0}.
Z
on
2
Therfire only
That t is a polynomial.
at zo
to
This is
n
an. Z
|2|=1.
f(z) = am - 2²,
Z
fonction and
That f₁2²) = C. 2².
1
+ (-1/2)
So
/
have
possiblity
This
then
f is a polynomial.
have
at most
Case it has to be
by
pole
possible Sine
meas
So of has pole at
But by
|an| =!
का
is fo=o.
That
|an| = |
2
is
ore
distinct
at z=0.
The Criteric"
Transcribed Image Text:Question:- Suppose that of is antive
121=1. y han
pone
|- f₁2)| = |
Solt:
The
first-
on
analytic
If of has
Symmetry
infinity.
Zero
function
f is entire.
We
the paint
Again
Lam of (w)
Now t
in
So fiz)
| f₁₂) | = 1
Zero
f would have
using gymorely
Henle
Com
which
-
prove
ㅏ
<\ {0}.
Z
on
2
Therfire only
That t is a polynomial.
at zo
to
This is
n
an. Z
|2|=1.
f(z) = am - 2²,
Z
fonction and
That f₁2²) = C. 2².
1
+ (-1/2)
So
/
have
possiblity
This
then
f is a polynomial.
have
at most
Case it has to be
by
pole
possible Sine
meas
So of has pole at
But by
|an| =!
का
is fo=o.
That
|an| = |
2
is
ore
distinct
at z=0.
The Criteric
Expert Solution

Step 1
Given that is entire entire function and on .
To prove that
Step by step
Solved in 2 steps

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