Question: Since the flow rate through the rectangular cross-section channel in the figure is Q=20 m3/s, the channel bottom slope is lo=1/200 and n=0.03 channel bottom width B=5 m, a) The critical depth value ( yc ) that passes the flow through the channel at the minimum specific energy level, b) The critical channel slope ( Ic) and the flow regime ( by comparing Ic and lo ) that pass the flow through the channel at the critical depth, c) Uniform flow depth (yo),

Q: Water flows through a 1.8-m-wide rectangular channel with a Manning coefficient of n = 0.012. If the…

A: The expression for the flow area of the channel is given as, Here, AC is the flow area of the…

Q: 5. When depth of flow is more than critical depth, it is called as: a) Supercritical flow b)…

A: 5. The water profile is classified based on the flow of water longitudinally. They are classified as…

Q: only HANDWRITTEN answer needed ( NOT TYPED)

A: B = 2.9 m z = 0.2 m d1 = 2.54 m d2 = 1.77 m

Q: When the channel of triangular cross section shown in the figure below was new, a flowrate of Q…

A: Given data:- The value of flowrate of Q caused the water to reach, L1=1.9 m Use formula:-  Q=AV…

Q: This problem refers to the sketch shown in Figure 2. If the discharge in the channel (n = 0.028) is…

A: Manning coefficient (n) = 0.028Discharge (Q) = 6 m3/sec Depth of flow (y) = 1.8m Maximum velocity…

Q: weir installed at the end of a rectangular channel controls the flow of water. The rate of flow is…

A: To find percentage error in discharge measured

Q: Consider an irrotational region of flow composed of a line source of strength V. /L at location (−a,…

A: The figure is shown below,

Q: form flow of water in a wide channel with a velocity of 8 m/s and flow depth of 0.8 m. Water flows…

A: Data provided-   V1 = 8 m/s , y1 =0.8 m     Total energy at (1) =E1   E1 = y1 +V122g=(0.8+822×9.81)…

Q: A wide river with a water surface elevation 1/8000 of depth of flow D. If the depth of flow in the…

A: Discharge ratio- Q1/Q2=2.58 Surface slope decrease by 40%, Elevation=1/8000. % change in discharge=?

Q: Water flows downward in a pipe of 600 mm diameter at the rate of 2 m³/s. It then enters a conical…

A: Rate of flow Q=2m3/sdiameter of conical duct DA=600mm.Diameter of conical duct DB=300mm.Length of…

Highway Drainage

Highway drainage is the process of extracting and regulating the excess surface water on the pavement by giving the desired slope. The construction of a highway drain helps to divert the water present on the surface, and sub-grade by the means of slope. Highway drainage systems are a necessary part of smooth functioning of traffic, since the highway drainage systems provide proper disposal of unwanted substances from the highways.