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Question reminder: Using the formula from a) tn = 100(0.8)~1, substitute 9 in for n to find the 9th term: to = 100(0.8)n-1

Question reminder: Using the formula from a) tn = 100(0.8)~1, substitute 9 in for n to find the 9th term: to = 100(0.8)n-1

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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please show me every step to this question, im confused how we get the number 0.16777216

Solution Question reminder: Using the formula from a) t, = 100(0.8)*-1, substitute 9 in for n to find the 9th term: tn = 100(0.8)n-1 t, = 100(0.8)°-1 t9 = 100(0.8) to = 100(0.16777216) t9 = 16.777216 t9 = 16.78 %3D 8 The 9th term in the sequence is 16.78. Notice that the decimal values are not rounded throughout the calculation of the question, only the final answer is rounded.
Transcribed Image Text:Solution Question reminder: Using the formula from a) t, = 100(0.8)*-1, substitute 9 in for n to find the 9th term: tn = 100(0.8)n-1 t, = 100(0.8)°-1 t9 = 100(0.8) to = 100(0.16777216) t9 = 16.777216 t9 = 16.78 %3D 8 The 9th term in the sequence is 16.78. Notice that the decimal values are not rounded throughout the calculation of the question, only the final answer is rounded.
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