Question Porosity is a measure of the void or empty spaces in a material and is a fraction of the volume of voids over the total volume. The density of the solid material used to create 11 pieces of 1.39 cm diameter and 0.65 cm height cylindrical beads is determined to be 2.24 g/mL. These beads were then placed in a flask and was filled to the 40 mL mark with a salt solution. The total weight measured of the beads and the salt solution was 51.96 g. Upon further inspection, it was found that manufacturing defects caused the measured porosity of the beads to be at 26%. Assuming that the solution was able to fully fill the empty spaces inside the beads, calculate the density of the salt

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
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I would like to ask if how did you get 40 in step 8 as the volume in the solution?
.l SMART ?
12:00 PM
3%|
Question
Porosity is a measure of the void or empty spaces
in a material and is a fraction of the volume of
voids over the total volume. The density of the solid
material used to create 11 pieces of 1.39 cm
diameter and 0.65 cm height cylindrical beads is
determined to be 2.24 g/mL. These beads were
then placed in a flask and was filled to the 40 mL
mark with a salt solution. The total weight
measured of the beads and the salt solution was
51.96 g. Upon further inspection, it was found that
manufacturing defects caused the measured
porosity of the beads to be at 26%. Assuming that
the solution was able to fully fill the empty spaces
inside the beads, calculate the density of the salt
solution.
Expert Answer
Step1
a)
Transcribed Image Text:.l SMART ? 12:00 PM 3%| Question Porosity is a measure of the void or empty spaces in a material and is a fraction of the volume of voids over the total volume. The density of the solid material used to create 11 pieces of 1.39 cm diameter and 0.65 cm height cylindrical beads is determined to be 2.24 g/mL. These beads were then placed in a flask and was filled to the 40 mL mark with a salt solution. The total weight measured of the beads and the salt solution was 51.96 g. Upon further inspection, it was found that manufacturing defects caused the measured porosity of the beads to be at 26%. Assuming that the solution was able to fully fill the empty spaces inside the beads, calculate the density of the salt solution. Expert Answer Step1 a)
It is given that the mass of the beads and the salt
solution is 51.96 g.
Step7
g)
Therefore, the mass of the salt solution is
51. 96 – Mass of bead=51.96 – 17. 985
=33. 975 g
Step8
h)
Now, the density of the salt solution is
Mass
Density=
Volume
33.975
40
=0. 85 g/ml
Step9
i)
The density of the salt solution is 0.85 g/ml.
Transcribed Image Text:It is given that the mass of the beads and the salt solution is 51.96 g. Step7 g) Therefore, the mass of the salt solution is 51. 96 – Mass of bead=51.96 – 17. 985 =33. 975 g Step8 h) Now, the density of the salt solution is Mass Density= Volume 33.975 40 =0. 85 g/ml Step9 i) The density of the salt solution is 0.85 g/ml.
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