Find f(1), f(2), f(3), and f(4) if f(n) is defined recur- sively by f(0) = 1 and for n = 0, 1, 2,... a) f(n+1)=f(n) +2. b) f(n+1)=3f(n). c) f(n+1)=27(n) d) f(n+1)= f(n)² + f(n) +1.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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\Question No.2
Find f(1), f(2), S (3), and f(4) if s(n) is defined recur-
sively by f(0) = 1 and for n = 0, 1, 2, ...
a) f(n + 1) = f (n) + 2.
b) f (n + 1) =3f (n).
c) f(n + 1) = 2/(W).
d) f(n + 1) = r (n)? + S(n) + 1.
Find f(1), S(2), S (3), f (4), and f(5) if f (n) is defined
recursively by f (0) = 3 and for n = 0, 1, 2,...
a) f(n + 1) = -2/ (n).
b) f (n + 1) = 3f (n) +7.
c) f(n + 1) = f(n)? – 2f (n) –- 2.
d) f(n + 1) = 3/(m)/3.
Find f (2), f(3), f(4), and f(5) if f is defined recur-
sively by f(0) =-1, S(1) = 2, and for n= 1, 2, ...
a) f(n + 1) = (n)+ 3f (n – 1).
b) f(n + 1) = f (n)?f (n – 1).
c) f(n + 1) = 3/ (n)2 – 45 (n - 1)2.
d) f(n + 1) = f (n – 1)/5(n).
Find f(2), S(3), S(4), and f(5) if s is defined recur-
sively by f(0) = S(1) = 1 and for n = 1, 2, ...
a) S(n + 1) = f (n) - S(n – 1).
b) f (n + 1) = f (n)/ (n - 1).
c) f(n + 1) =(n)2 + s(n - 1).
d) f(n + 1) = (n)/S(n - 1).
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Transcribed Image Text:\Question No.2 Find f(1), f(2), S (3), and f(4) if s(n) is defined recur- sively by f(0) = 1 and for n = 0, 1, 2, ... a) f(n + 1) = f (n) + 2. b) f (n + 1) =3f (n). c) f(n + 1) = 2/(W). d) f(n + 1) = r (n)? + S(n) + 1. Find f(1), S(2), S (3), f (4), and f(5) if f (n) is defined recursively by f (0) = 3 and for n = 0, 1, 2,... a) f(n + 1) = -2/ (n). b) f (n + 1) = 3f (n) +7. c) f(n + 1) = f(n)? – 2f (n) –- 2. d) f(n + 1) = 3/(m)/3. Find f (2), f(3), f(4), and f(5) if f is defined recur- sively by f(0) =-1, S(1) = 2, and for n= 1, 2, ... a) f(n + 1) = (n)+ 3f (n – 1). b) f(n + 1) = f (n)?f (n – 1). c) f(n + 1) = 3/ (n)2 – 45 (n - 1)2. d) f(n + 1) = f (n – 1)/5(n). Find f(2), S(3), S(4), and f(5) if s is defined recur- sively by f(0) = S(1) = 1 and for n = 1, 2, ... a) S(n + 1) = f (n) - S(n – 1). b) f (n + 1) = f (n)/ (n - 1). c) f(n + 1) =(n)2 + s(n - 1). d) f(n + 1) = (n)/S(n - 1). %3D %3D %3D
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