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? QUESTION ill in the P(X=x) values to give a legitimate probability distribution for the discrete random variable X, whose possible values are -5, -2, -1, 1, and 2. P(X = x) Value x of X -5 -2 -1 1 0.30 0.12 0.18 0

? QUESTION ill in the P(X=x) values to give a legitimate probability distribution for the discrete random variable X, whose possible values are -5, -2, -1, 1, and 2. P(X = x) Value x of X -5 -2 -1 1 0.30 0.12 0.18 0

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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E k ? QUESTION Fill in the P(X=x) values to give a legitimate probability distribution for the discrete random variable X, whose possible values are -5, -2, -1, 1, and 2. Value x of X P(X=x) esc 1 OSTATISTICS Discrete probability distribution: Basic A ntrol -5 -2 -1 1 00 EXPLANATION ! 1 Tonya Harding Te....pdf A 2 More Practice FI The values that the discrete random variable X may take are -5, -2, -1, 1, and 2. Thus, it must be that we have the following. P(X=-5)+P(X=-2) + P(X=-1) + P(X=1)+P(X=2)=1 In the above, 0≤P (X=x) ≤1 for x=-5, -2, -1, 1, 2. From the information given, we have this. Q 0.30+0.12+0.18+ P(X=1) +P(X=2)=1 A U 0.30 N 0.12 2 0.18 0 38 0 F2 W S #3 X H option command 20 F3 E D $ 4 C 899 F4 R F % сла 5 V F5 H T G MacBook Air A 6 F6 Y & 7 H aa F7 U ΒΙΝ Ⓒ2022 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility * 8 J DII FB - 1 0000 0/5 ( 9 1 K M DD FO 0 < I 2 ) 0 L F10 P . V - > .... I 31 F11 { + [ command option = ? I I Aleay Show All F12 } 1 ▾
Transcribed Image Text:E k ? QUESTION Fill in the P(X=x) values to give a legitimate probability distribution for the discrete random variable X, whose possible values are -5, -2, -1, 1, and 2. Value x of X P(X=x) esc 1 OSTATISTICS Discrete probability distribution: Basic A ntrol -5 -2 -1 1 00 EXPLANATION ! 1 Tonya Harding Te....pdf A 2 More Practice FI The values that the discrete random variable X may take are -5, -2, -1, 1, and 2. Thus, it must be that we have the following. P(X=-5)+P(X=-2) + P(X=-1) + P(X=1)+P(X=2)=1 In the above, 0≤P (X=x) ≤1 for x=-5, -2, -1, 1, 2. From the information given, we have this. Q 0.30+0.12+0.18+ P(X=1) +P(X=2)=1 A U 0.30 N 0.12 2 0.18 0 38 0 F2 W S #3 X H option command 20 F3 E D $ 4 C 899 F4 R F % сла 5 V F5 H T G MacBook Air A 6 F6 Y & 7 H aa F7 U ΒΙΝ Ⓒ2022 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility * 8 J DII FB - 1 0000 0/5 ( 9 1 K M DD FO 0 < I 2 ) 0 L F10 P . V - > .... I 31 F11 { + [ command option = ? I I Aleay Show All F12 } 1 ▾
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