Identify the big-O time for these void functions ### Question:Identify the big-O time complexity of each of the following functions:#### Function f1:```cppvoid f1(int n) { for(int i=0; i<(3*n+n); ++i) { cout << i << endl; } for(int i=0; i<(10*n); ++i) { cout << i << endl; }}```- **Explanation:** - The first loop runs for `4n` times (`3n + n`), and the second loop runs for `10n` times. - Overall, this results in a time complexity of **O(n)**.#### Function f2:```cppvoid f2(int n) { if(n==0) { return; } f2(n-1); f2(n-3);}```- **Explanation:** - This function makes two recursive calls: one reducing `n` by 1 and the other by 3. - The recurrence relation is **T(n) = T(n-1) + T(n-3) + O(1)**. - The time complexity is approximately **O(2^n/3)**, which simplifies to **O(2^(n/3))** or approximately **O(2^n)** in complexity analysis terms.#### Function f3:```cppvoid f3(int n) { for(int i=0; i

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Question: Identify the big-O time complexity of each of the following functions: void f1(int n) { } for (int i=0; i<(3*n+n); ++i) { cout << i << endl; } } for (int i=0; i< (10*n); ++i) { cout << i << endl; void f2 (int n) { if(n==0) { return; } f2 (n-1); f2 (n-3); void f3 (int n) { for (int i=0; i

Question: Identify the big-O time complexity of each of the following functions: void f1(int n) { } for (int i=0; i<(3n+n); ++i) { cout << i << endl; } } for (int i=0; i< (10n); ++i) { cout << i << endl; void f2 (int n) { if(n==0) { return; } f2 (n-1); f2 (n-3); void f3 (int n) { for (int i=0; i