QUestion Help v The data given to the right includes data from 45 candies, and 9 of them are red. The company that makes the candy claims that 29% of its candies are red. Use the sample data to construct a 95% confidence interval estimate of the percentage of red candies. What do you conclude about the claim of 29%? Weights (g) of a Sample Bag of Candy Red Blue 0.968 0.814 0.987 0.915 0.855 0.918 0.702 Brown Green Yellow 0.767 0.753 0.815 0.835 0.805 0.954 0.916 0.801 0.768 0.766 0.898 0.708 0.927 0.781 0.896 0.934 0.892 0.801 Construct a 95% confidence interval estimate of the population percentage of candies that are red. 0.786 0.881 0.817 %

QUestion Help v The data given to the right includes data from 45 candies, and 9 of them are red. The company that makes the candy claims that 29% of its candies are red. Use the sample data to construct a 95% confidence interval estimate of the percentage of red candies. What do you conclude about the claim of 29%? Weights (g) of a Sample Bag of Candy Red Blue 0.968 0.814 0.987 0.915 0.855 0.918 0.702 Brown Green Yellow 0.767 0.753 0.815 0.835 0.805 0.954 0.916 0.801 0.768 0.766 0.898 0.708 0.927 0.781 0.896 0.934 0.892 0.801 Construct a 95% confidence interval estimate of the population percentage of candies that are red. 0.786 0.881 0.817 %

Name: Question HelpThe data given to the right includes data from 45 candie
Uploaded: 2024-03-20T07:07:12.000Z
Channel: Bartleby
Description: Question HelpThe data given to the right includes data from 45 candies, and 9 of them are red. The company that makes the candyclaims that 29% of its candies are red. Use the sample data to construct a 95% confidence interval estimate of thepercenta

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

The data given below gives the marks scored by six second year students taking BSc. Engineering: 87, 65,73, 56, 95 and 62. Construct a 95% confidence interval for the students’ mean weight.
An insurance company selected samples of clients under 18 years of age and over 18 and recorded the number of accidents they had in the previous year. We are interested in determining if the accident proportions differ between the two age groups. The results are shown below. a =0.05 Under age of 18 Over age of 18 n₂ =500 n₁ = 480 Number of accidents = 160 Number of accidents = 140 The test statistic is A 90% confidence interval for the proportion between two age groups is approximately Given a 5% level of significance, what decision should be reached about the null hypothesis
You do a study of hypnotherapy to determine how effective it is in increasing the number of hours of sleep subjects get each night. You measure hours of sleep for 12 subjects with the following results. Construct a 90% confidence interval for the mean number of hours slept for the population (assumed normal) from which you took the data. (Give your answer rounded to the nearest 4 decimal places if necessary.) {7.8, 8.9, 9.5, 11.2, 11.5, 8.3, 11.8, 8.4, 8, 8.4, 10.1, 10.3} (?,? )
Given that degrees of freedom is 18 at 95% confidence level, the value of t =________.Select one:a. 1.383b. -1.717c. 2.101d. -1.383
A College Alcohol Study interviewed an SRS of 1000 college students about their drinking habits. Suppose that half of all college students "drink to get drunk" at least once in a while. That is sample proportion, p-hat 0.5. %3D 9. Estimate a 95% confidence interval for the actual percentage among all students. Round the number to nearest hundredth. O47% to 53% O 50% to 55% 43% to 52% O 44% to 56%
Your statistics instructor claims that 60 percent of the students who take her Elementary Statistics class go through life feeling more enriched. For some reason that she can't quite figure out, most people don't believe her. You decide to check this out on your own. You randomly survey 64 of her past Elementary Statistics students and find that 34 feel more enriched as a result of her class. Construct a 95% confidence interval for the true mean or proportion. Round to the nearest hundredth (2 decimal places). ( , )
In a sample of 7 observations, the values are 17, 11, 12, 13, 14, 15. 16. Find the 95% confidence interval for the population mean. O A. (5.00, 9.00) O B. (4.00, 8.00) OC (12.00, 16.00) OD.(11.00, 15.00)
A quality-conscious disk manufacturer wishes to know the fraction of disks his company makes which are defective. Step 2 of 2: Suppose a sample of 542 floppy disks is drawn. Of these disks, 37 were defective. Using the data, construct the 95% confidence interval for the population proportion of disks which are defective. Round your answers to three decimal places.
You sample 1O0 people to see if they have been to the grocery store in the past week, and find that 85% (.85) of them have been. What is the 95% confidence interval for this study? Leave your answer in decimal format to 2 decimal places. In other words, .04 instead of 3.6% or .11 instead of 11.4%.. O .78 to .92 .84 to .85 O .60 to 1.10 O .60 to 1.00 .15 to 1.55
A random sample of high school students is used to estimate the mean time all high school students study for Algebra II tests. A 99% confidence interval based on this sample is: 1.7 hours to 3.1 hours. What is the sample mean?
Tourism is extremely important to the economy of Florida. Hotel occupancy is an often-reported measure of visitor volume and visitor activity (Orlando Sentinel, May 19, 2018). Hotel occupancy data for February in two consecutive years are as follows, current year previous year occupied rooms 1470 1458 total rooms 1750 1800 a)What is the 95% confidence interval estimate of the change in occupancy for the one-year period? b)Do you think officials will be pleased with the results? c) Using a 0.05 level of significance, test the hypothesis that there has been an increase in the proportion of rooms occupied over the one-year period.
Suppose you are given the following information from a sample of data: variance is 484 the number of observations in the sample is 65 for a confidence level of 96%, calculate the margin of error