Question Enumerate() function / break / loop-else In python, when apply relational operators (e.g., >, <) to two list variables, the evaluation depends on the comparison of the first mismatched element from the two list. For example, if x = [1, 5, 2] and y = [1, 4, 3, 5], then evaluating x < y first evaluates that 1 and 1 match. The next elements do not match, so 5 < 4 is evaluated, which produces a value of False for the expression of x < y. In the case of x = [1, 5] and y = [1, 5, 3], x > y evaluates to False In the case of x = [1, 5] and y = [1, 4, 3], x > y evaluates to True Write a program to implement such comparison between two lists of numbers. Requirement: Use enumerate() function Use break statement Use loop-else structure Your code should handle the case of lists of different lengths Hint: Start your program as follows (Try to think about why this is necessary) and finish the rest of the program to compare the two list variables longer and shorter: ###x and y could be any given lists of numbers x = (1, 5, 3] y - (1, 6] len_x = len(x) len_y = len(y) if len_x <= len_y: longer = y shorter = x else: longer = x shorter = y Sample outputs for different number list x and number list y: (1, 5, 2] > [1, 4, 3, 5] [1, 5] < [1, 5, 3] (1, 5] > [1, 4, 3] [1, 5] == [1, 5]
Question Enumerate() function / break / loop-else In python, when apply relational operators (e.g., >, <) to two list variables, the evaluation depends on the comparison of the first mismatched element from the two list. For example, if x = [1, 5, 2] and y = [1, 4, 3, 5], then evaluating x < y first evaluates that 1 and 1 match. The next elements do not match, so 5 < 4 is evaluated, which produces a value of False for the expression of x < y. In the case of x = [1, 5] and y = [1, 5, 3], x > y evaluates to False In the case of x = [1, 5] and y = [1, 4, 3], x > y evaluates to True Write a program to implement such comparison between two lists of numbers. Requirement: Use enumerate() function Use break statement Use loop-else structure Your code should handle the case of lists of different lengths Hint: Start your program as follows (Try to think about why this is necessary) and finish the rest of the program to compare the two list variables longer and shorter: ###x and y could be any given lists of numbers x = (1, 5, 3] y - (1, 6] len_x = len(x) len_y = len(y) if len_x <= len_y: longer = y shorter = x else: longer = x shorter = y Sample outputs for different number list x and number list y: (1, 5, 2] > [1, 4, 3, 5] [1, 5] < [1, 5, 3] (1, 5] > [1, 4, 3] [1, 5] == [1, 5]
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Enumerate() function / break / loop-else
In python, when apply relational operators (e.g., >, <) to two list variables, the evaluation
depends on the comparison of the first mismatched element from the two list.
For example, if x = [1, 5, 2] and y = [1, 4, 3, 5], then evaluating x < y first evaluates that 1 and 1
match. The next elements do not match, so 5 <4 is evaluated, which produces a value of False
for the expression of x < y.
In the case of x =[1, 5] and y = [1, 5, 3], x > y evaluates to False
In the case of x =[1, 5] and y = [1, 4, 3], x > y evaluates to True
Write a program to implement such comparison between two lists of numbers.
Requirement: Use enumerate() function
Use break statement
Use loop-else structure
Your code should handle the case of lists of different lengths
Hint: Start your program as follows (Try to think about why this is necessary) and finish the rest
of the program to compare the two list variables longer and shorter:
###x and y could be any given lists of numbers
x = [1, 5, 3]
y = (1, 6]
len_x = len(x)
len_y = len(y)
if len_x <= len_y:
longer = y
shorter == x
else:
longer = x
shorter = y
Sample outputs for different number list x and number list y:
[1, 5, 21 > [1, 4, 3, 5]
[1, 5] < [1, 5, 3]
|[1, 5] > [1, 4, 3]
|[1, 5] == [1, 5]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F434fae3a-6f85-449f-8380-68e6452fa17b%2F2a76fc94-8224-464d-86a4-062943fef473%2Fadac265_processed.png&w=3840&q=75)
Transcribed Image Text:Question
Enumerate() function / break / loop-else
In python, when apply relational operators (e.g., >, <) to two list variables, the evaluation
depends on the comparison of the first mismatched element from the two list.
For example, if x = [1, 5, 2] and y = [1, 4, 3, 5], then evaluating x < y first evaluates that 1 and 1
match. The next elements do not match, so 5 <4 is evaluated, which produces a value of False
for the expression of x < y.
In the case of x =[1, 5] and y = [1, 5, 3], x > y evaluates to False
In the case of x =[1, 5] and y = [1, 4, 3], x > y evaluates to True
Write a program to implement such comparison between two lists of numbers.
Requirement: Use enumerate() function
Use break statement
Use loop-else structure
Your code should handle the case of lists of different lengths
Hint: Start your program as follows (Try to think about why this is necessary) and finish the rest
of the program to compare the two list variables longer and shorter:
###x and y could be any given lists of numbers
x = [1, 5, 3]
y = (1, 6]
len_x = len(x)
len_y = len(y)
if len_x <= len_y:
longer = y
shorter == x
else:
longer = x
shorter = y
Sample outputs for different number list x and number list y:
[1, 5, 21 > [1, 4, 3, 5]
[1, 5] < [1, 5, 3]
|[1, 5] > [1, 4, 3]
|[1, 5] == [1, 5]
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