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Question Determine the sum of the convergent series below. Leave your answer as a fraction in terms of e. 8 n=1 e²n (-8)¹-n

Question Determine the sum of the convergent series below. Leave your answer as a fraction in terms of e. 8 n=1 e²n (-8)¹-n

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Question** Determine the sum of the convergent series below. \[ \sum_{n=1}^{\infty} e^{2n} (-8)^{1-n} \] Leave your answer as a fraction in terms of \(e\). **Response** Sorry, that's incorrect. Try again? The answer given was: \[ \sum_{n=1}^{\infty} e^{2n} (-8)^{1-n} = \frac{e^{2n}}{9} \] **Navigation Options** - **Feedback** - **View Answer** - **Submit**
Transcribed Image Text:**Question** Determine the sum of the convergent series below. \[ \sum_{n=1}^{\infty} e^{2n} (-8)^{1-n} \] Leave your answer as a fraction in terms of \(e\). **Response** Sorry, that's incorrect. Try again? The answer given was: \[ \sum_{n=1}^{\infty} e^{2n} (-8)^{1-n} = \frac{e^{2n}}{9} \] **Navigation Options** - **Feedback** - **View Answer** - **Submit**
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