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QUESTION: Determine the cubic structure of platinum if it forms a unit cell with a volume of 0.0595 nm^3. The atomic radius of platinum is 138 pm. *Please use the pictures provided (the formula and some values that can be substituted

QUESTION: Determine the cubic structure of platinum if it forms a unit cell with a volume of 0.0595 nm^3. The atomic radius of platinum is 138 pm. *Please use the pictures provided (the formula and some values that can be substituted

Chemistry: Principles and Practice
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter11: Liquids And Solids
Section: Chapter Questions
Problem 11.74QE
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QUESTION: Determine the cubic structure of platinum if it forms a unit cell with a volume of 0.0595 nm^3. The atomic radius of platinum is 138 pm.

*Please use the pictures provided (the formula and some values that can be substituted

P: nA VCNA Where: p density (g/cm³) n = no. of atoms/ unit cell A = atomic weight (g/mol) Important conversion factors 1 cm = 107 nm 1 cm = 10¹⁰ pm 1 cm = 10⁰ Å 1 nm = 10 Å Vc = volume / unit cell (cm³/unit cell) = a³ NA = Avogadro's number = 6.022x10²3 atoms/mol
Transcribed Image Text:P: nA VCNA Where: p density (g/cm³) n = no. of atoms/ unit cell A = atomic weight (g/mol) Important conversion factors 1 cm = 107 nm 1 cm = 10¹⁰ pm 1 cm = 10⁰ Å 1 nm = 10 Å Vc = volume / unit cell (cm³/unit cell) = a³ NA = Avogadro's number = 6.022x10²3 atoms/mol
Coordination number Number of atoms per unit cell APF (%) Relationship of r and a SC 6 1 52 r = 1 2 α BCC 8 2 68 r = √3 4 a FCC 12 4 74 r = √2 4 a
Transcribed Image Text:Coordination number Number of atoms per unit cell APF (%) Relationship of r and a SC 6 1 52 r = 1 2 α BCC 8 2 68 r = √3 4 a FCC 12 4 74 r = √2 4 a
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