* Question Completion Status: QUESTION 10 A researcher took a random sample of 100 students from a large university. She computed a 95% confidence interval to estimate the average weight of the students at this university. The confidence interval was too wide to provide a precise estimate. What could she do to produce a narrower confidence interval? T TTT Paragraph Arial 3 (12pt) v E - E 只i公 T T, 1¶' - - HTML CSS O f. Mashups 1□田 Words:0 Path: p Click Save and Submit to save and submit. Click Save All Answers to save all answers.

* Question Completion Status: QUESTION 10 A researcher took a random sample of 100 students from a large university. She computed a 95% confidence interval to estimate the average weight of the students at this university. The confidence interval was too wide to provide a precise estimate. What could she do to produce a narrower confidence interval? T TTT Paragraph Arial 3 (12pt) v E - E 只i公 T T, 1¶' - - HTML CSS O f. Mashups 1□田 Words:0 Path: p Click Save and Submit to save and submit. Click Save All Answers to save all answers.

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A random sample of 49 Europeans was asked how many days of vacation they take each year. The sample mean was 30 and the population standard deviation is known to be 4. What is the 99% confidence interval of the true population parameter describing average vacation days?
A random sample of n₁ = 217 people who live in a city were selected and 106 identified as a "dog person." A random sample of n₂ = 114 people who live in a rural area were selected and 66 identified as a "dog person." Find the 90% confidence interval for the difference in the proportion of people that live in a city who identify as a "dog person" and the proportion of people that live in a rural area who identify as a "dog person." Round answers to to 4 decimal places. < P1 P2 <
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Independent random samples are taken at a university to compare the average GPA of seniors to the average GPA of sophomores. Given a 90% confidence interval for the difference between the true average GPAs (seniors - sophomores) of (-0.05, 0.78), what can you conclude? Question 8 options: 1) There is no significant difference between the true average GPA for seniors and sophomores. 2) We do not have enough information to make a conclusion. 3) We are 90% confident that the average GPA of seniors is less than the average GPA of sophomores. 4) We are 90% confident that the average GPA of seniors is greater than the average GPA of sophomores. 5) We are 90% confident that the difference between the two sample GPAs falls within the interval.
A random sample of n₁ = 224 people who live in a city were selected and 90 identified as a "dog person." A random sample of n₂ = 95 people who live in a rural area were selected and 61 identified as a "dog person." Find the 95% confidence interval for the difference in the proportion of people that live in a city who identify as a "dog person" and the proportion of people that live in a rural area who identify as a "dog person." Round answers to to 4 decimal places. P1 P2
A random sample of n₁ = 269 people who live in a city were selected and 88 identified as a "dog person." A random sample of n2 = 90 people who live in a rural area were selected and 70 identified as a "dog person." Find the 99% confidence interval for the difference in the proportion of people that live in a city who identify as a "dog person" and the proportion of people that live in a rural area who identify as a "dog person." Round answers to to 4 decimal places. < P1 P2 <
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In order to estimate the average GPA of all students at SCC, we selected a random sample of 36 students and found that their average GPA is 2.1 with a s. d. of 0.8.Construct a 95% confidence interval for the average GPA of all students at SCC.
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The mean score on the math portion of the ACT for the year 2000 is μ = 20.7. A sample of 20 students in a local school district had a mean of 22.95. Using the sample, a 95% confidence interval estimate for the mean is (20.76, 25.14). State the point estimate for the mean ACT score for students. Based on this sample information , do you believe that the local students have a mean different from the general population? Why? 22.95 is in the center of the interval. The means are definitely not different. 22.95 is just outside the 95% confidence interval. Can't say the means are really different. 22.95 is not equal to 20.7. The means are definitely different. 20.7 is just outside the 95% confidence interval. Can't say the means are really different.
A random sample of high school seniors were asked whether they were applying for college. The resulting confidence interval for the proportion of students applying for college is (0.65,0.69). What is the margin of error?