Question Calculate the potential at a point P due to a charge of 4 × 10-´C located 9 cm away. Hence obtain the work done in bringing a charge of 2 x 10-°C from infinity to the point P. Does the answer depend on the path along which the charge is brought?
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Solved in 3 steps with 3 images
- Please show complete solutionWhat is the excess charge on a conducting sphere of radius r = 0.17 m if the potential of the sphere is 2000 V and V = 0 at infinity? Number UnitsThe figure shows two points A and B in a uniform electric field of magnitude 1200 N/C. A• 7.0 cm (a) The electric potential at A is –12 V. Find the electric potential at B. -6 g from point A at 13 m/s. The particle passes through point B (b) You launch a charged particle of mass 1.5 × 10 3.7 ms later. Find the particle's charge. 3.0cm
- For each of these calculations you may take that the electric potential is zero infinitely far away from the point charges.Direction: Using the understanding to Electric Potential and Energy. Solve for the following given the four charges shown below: GA = 6stat C go =5nC =15stat C A' Acm B CS bnnealWtYCamScanner 9stat C 3stat C (f) VDA (g) VBc (h) VcB ) VaD (k) VCD (1) If q = 3nC, what is WAC and WCA?Q1:- Three charges, q1 = 2 µC , q2 = -4 µC and q3 = 6 µC are located at a distance of (50 cm ) from a point (P). Determine the distance of another chatrge (q4 = -4µC ), which makes zero potential at point (P). %3D
- Current Attempt in Progress In the figure particles with charges q1 +3e and q2-12e are fixed in place with a separation of d = 28.3 cm. With V-0 at infinity, what are the finite (a) positive and (b) negative values of x at which the net electric potential on the x axis is zero? (a) Number (b) Number Units Unitsb) d) NISANTAS About Electric Potential (Continuous charge density) 1.12 x 10¹2 V 1.12 x 10-12 V -1.12 x 10-12 V -1.12 x 10¹2 V dq √²+x² x As given in Figure, find the electric potential value at a point 'P' located on the perpendicular central axis of a uniformly charged ring of radius 'a' and total charge 'Q' by taking a = 5.00 × 10² m, x = 12.00 × 10² m, and Q = 1.60 x 10-¹⁹ C. Hint: Use V = k₁ *V = k₁|4² r where r = √a² + x² and 1 N.m² 4x€o C² result to the nearest numeric value. 9.00 × 10⁹ -. Round your15
- The figure shows a cube with a point charge of magnitude 5.98 nC at each corner. 4 of the Charges are positive and the rest are negative. if the cube has sides of length 24.2m and the potential at infinity is zero, what is the potential at the center of the cube?" 出1. (a) What is the absolute potential at each ofthe following distances from a charge of +2.0μC in air: r = 10 cm and r = 50 cm? (b) Howmuch work is required to carry a 0.05-μCcharge from the point at r = 50 cm to that at r= 10 cm?#2 question only. Thank you.