Question B. 2 1 0. 2 0 1 B1 : 0 2 0 and B2 0 2 0 %3D 0 0 2 0 0 2

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Chapter2: Second-order Linear Odes
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I already  have Question: A  answer,  please solve Q:B and (Verify whether the two given matrices are similar. To justify your answers perform suitable calculations or provide the Jordan form.)

1. Verify whether the two given matrices are similar. To justify your answers
perform suitable calculations or provide the Jordan form.
Question A.
21
2 0
and A2
%3D
0 2
Question B.
2 1 0
2 0 1
B1 =
020
and B2 =
0 2 0
0 0 2
00 2
Transcribed Image Text:1. Verify whether the two given matrices are similar. To justify your answers perform suitable calculations or provide the Jordan form. Question A. 21 2 0 and A2 %3D 0 2 Question B. 2 1 0 2 0 1 B1 = 020 and B2 = 0 2 0 0 0 2 00 2
Step 1
Note: Since you have asked multiple questions, we
will solve the first question for you. If you want any
specific question to be solved then please specify
the question number or post only that question.
Introduction:
If there is an invertible matrix M such that
M-'AM, two matrices A and B are identical.
В
Step 2
We have to find whether the given matrices are
similar or not.
(a) It is given that the matrix Aj and A2 are
A1
and A2
1
Find the determinant of matrices Aj and A2.
2 1
JA1|=
0 2
=4 – 0
=4
2 0|
JA2|=
1 2
=4 – 0
=4
So, here det(A1) = det(A2) = 4 and a trace of these
matrices are tr(A1) = tr(A2) = 4.
Step 3
Now find the characteristics polynomial of the
matrix Aj is given by
JA1 – Al|=0
2 – 2
1
2 – 2
(2 – 2)? – 0=0
=1 = 2,2
Now, find the eigenvector corresponding to 1 = 2.
1
%3D
0 2- 2
0 + y=0
So, the basis for the solution set is
Step 4
Since the multiplicity of eigenvalue i = 2 is 2, then
the solution set corresponds to
2 – 2
1
is
2 – 2
So, the matrix A1 can be written as,
2 1
1 0
2 1
0 2
Hence we cannot express matrix Aj as
A1 = M-'A2M. Hence the matrices A1 and A2 are
not similar.
Transcribed Image Text:Step 1 Note: Since you have asked multiple questions, we will solve the first question for you. If you want any specific question to be solved then please specify the question number or post only that question. Introduction: If there is an invertible matrix M such that M-'AM, two matrices A and B are identical. В Step 2 We have to find whether the given matrices are similar or not. (a) It is given that the matrix Aj and A2 are A1 and A2 1 Find the determinant of matrices Aj and A2. 2 1 JA1|= 0 2 =4 – 0 =4 2 0| JA2|= 1 2 =4 – 0 =4 So, here det(A1) = det(A2) = 4 and a trace of these matrices are tr(A1) = tr(A2) = 4. Step 3 Now find the characteristics polynomial of the matrix Aj is given by JA1 – Al|=0 2 – 2 1 2 – 2 (2 – 2)? – 0=0 =1 = 2,2 Now, find the eigenvector corresponding to 1 = 2. 1 %3D 0 2- 2 0 + y=0 So, the basis for the solution set is Step 4 Since the multiplicity of eigenvalue i = 2 is 2, then the solution set corresponds to 2 – 2 1 is 2 – 2 So, the matrix A1 can be written as, 2 1 1 0 2 1 0 2 Hence we cannot express matrix Aj as A1 = M-'A2M. Hence the matrices A1 and A2 are not similar.
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