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Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Educational Content: Evaluating Function Comparisons**

**Question 5: Analyzing Function Values**

**Graph Analysis:**
Displayed is a graph of a function \(f(x)\). The function appears to oscillate, dipping and peaking at various points within the domain exemplified in the graph (ranging from -4 to 4 on the x-axis and -4 to 4 on the y-axis). Notable points include local maxima and minima where the function changes direction.

**Function Definition:**
Given the function \(g(x) = (x - 3)^2 - 5\), we are asked to analyze and determine the relationship between the values of \(g(x)\) and the values of the function \(f(x)\) graphed above.

**Possible Statements:**
A. \(g(2) < f(3.5)\)
B. \(g(2) > f(3.5)\)
C. \(g(2) = f(3.5)\)
D. No comparison can be made because \(f(3.5)\) cannot be determined.
E. No comparison can be made because \(g(2)\) cannot be determined.

**Steps to Determine the Values:**

1. **Evaluate \(g(2)\):**
   \[
   g(2) = (2 - 3)^2 - 5 = 1 - 5 = -4
   \]

2. **Evaluate \(f(3.5)\) from the Graph:**
   - Locate \(x = 3.5\) on the x-axis.
   - Identify the corresponding y-value on the graph.
   On inspection of the graph, when \(x = 3.5\), \(y\) is approximately -0.5.

3. **Comparison:**
   - We know \(g(2) = -4\).
   - From the graph, \(f(3.5) \approx -0.5\).

4. **Conclusion:**
   - Since \(-4 < -0.5\), the correct statement is:
     \[
     \boxed{A. \, g(2) < f(3.5)}
     \]

This analysis method ensures an understanding of how to evaluate and compare function values using a given algebraic expression and a graph.
Transcribed Image Text:**Educational Content: Evaluating Function Comparisons** **Question 5: Analyzing Function Values** **Graph Analysis:** Displayed is a graph of a function \(f(x)\). The function appears to oscillate, dipping and peaking at various points within the domain exemplified in the graph (ranging from -4 to 4 on the x-axis and -4 to 4 on the y-axis). Notable points include local maxima and minima where the function changes direction. **Function Definition:** Given the function \(g(x) = (x - 3)^2 - 5\), we are asked to analyze and determine the relationship between the values of \(g(x)\) and the values of the function \(f(x)\) graphed above. **Possible Statements:** A. \(g(2) < f(3.5)\) B. \(g(2) > f(3.5)\) C. \(g(2) = f(3.5)\) D. No comparison can be made because \(f(3.5)\) cannot be determined. E. No comparison can be made because \(g(2)\) cannot be determined. **Steps to Determine the Values:** 1. **Evaluate \(g(2)\):** \[ g(2) = (2 - 3)^2 - 5 = 1 - 5 = -4 \] 2. **Evaluate \(f(3.5)\) from the Graph:** - Locate \(x = 3.5\) on the x-axis. - Identify the corresponding y-value on the graph. On inspection of the graph, when \(x = 3.5\), \(y\) is approximately -0.5. 3. **Comparison:** - We know \(g(2) = -4\). - From the graph, \(f(3.5) \approx -0.5\). 4. **Conclusion:** - Since \(-4 < -0.5\), the correct statement is: \[ \boxed{A. \, g(2) < f(3.5)} \] This analysis method ensures an understanding of how to evaluate and compare function values using a given algebraic expression and a graph.
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